Error: Unknown runtime error in ie while using ajax

**vjayis** · Mar 19 '08, 10:44 AM

Error: Unknown runtime error in ie while using ajax

hi
when i m trying to fetch data from one page to another page using ajax, i get an error message in IE., but it runs well in firefox., could anyone help me.,

here is my javascript code.,

[HTML]<script type="text/javascript">
var id;
var action;
function httprequest(id, action)
{

var xmlhttp;
try
{
xmlhttp=new XMLHttpRequest( );
}
catch(e)
{
try
{
xmlhttp=new Activexobject(" Msxml2.XMLHTTP" );
}
catch(e)
{
try
{
xmlhttp=new Activexobject(" MICROSOFT.XMLHT TP")
}
catch(e)
{
alert("ur browser doesnot support Ajax");
return false;
}
}

}
xmlhttp.onready statechange=fun ction()
{
if(xmlhttp.read yState==4)
{
document.getEle mentById("ajax" ).innerHTML=xml http.responseTe xt;
}
}

xmlhttp.open("G ET","url/"ajax.php?id="+ id+"&action="+a ction,true);
xmlhttp.send(nu ll);
}

function hidden(id,actio n)
{
httprequest(id, action)
}
</script>

<table id="ajax">------Place where i fetch data from another page and display---------
<tr><td><a onclick="hidden ('1','next')">n ext</a></td></tr>
</table>

[/HTML]
Could anyone help me.,
Thanks.,
vijay

**vjayis** · Mar 19 '08, 10:45 AM

Error: Unknown runtime error in ie

hi
when i m trying to fetch data from one page to another page using ajax, i get an error message in IE., but it runs well in firefox., could anyone help me.,

here is my javascript code.,

Code:

<script type="text/javascript">
var id;
var action;
function httprequest(id,action)
{

var xmlhttp;
try
{
xmlhttp=new XMLHttpRequest();
}
catch(e)
{
try
{
xmlhttp=new Activexobject("Msxml2.XMLHTTP");
}
catch(e)
{
try
{
xmlhttp=new Activexobject("MICROSOFT.XMLHTTP")
}
catch(e)
{
alert("ur browser doesnot support Ajax");
return false;
}
}

}
xmlhttp.onreadystatechange=function()
{
if(xmlhttp.readyState==4)
{
document.getElementById("ajax").innerHTML=xmlhttp.responseText;
}
}

xmlhttp.open("GET","url/"ajax.php?id="+id+"&action="+action,true);
xmlhttp.send(null);
}

function hidden(id,action)
{
httprequest(id,action)
}
</script>


<table id="ajax">------Place where i fetch data from another page and display---------
<tr><td><a onclick="hidden('1','next')">next</a></td></tr>
</table>

Could anyone help me.,
Thanks.,
vijay

**rpnew** · Mar 19 '08, 10:50 AM

Originally posted by vjayis

hi
when i m trying to fetch data from one page to another page using ajax, i get an error message in IE., but it runs well in firefox., could anyone help me.,

here is my javascript code.,

<script type="text/javascript">
var id;
var action;
function httprequest(id, action)
{

var xmlhttp;
try
{
xmlhttp=new XMLHttpRequest( );
}
catch(e)
{
try
{
xmlhttp=new Activexobject(" Msxml2.XMLHTTP" );
}
catch(e)
{
try
{
xmlhttp=new Activexobject(" MICROSOFT.XMLHT TP")
}
catch(e)
{
alert("ur browser doesnot support Ajax");
return false;
}
}

}
xmlhttp.onready statechange=fun ction()
{
if(xmlhttp.read yState==4)
{
document.getEle mentById("ajax" ).innerHTML=xml http.responseTe xt;
}
}

xmlhttp.open("G ET","url/"ajax.php?id="+ id+"&action="+a ction,true);
xmlhttp.send(nu ll);
}

function hidden(id,actio n)
{
httprequest(id, action)
}
</script>

<table id="ajax">------Place where i fetch data from another page and display---------
<tr><td><a onclick="hidden ('1','next')">n ext</a></td></tr>
</table>

Could anyone help me.,
Thanks.,
vijay

Hi,

What is the error that you are getting??

Regards,
RP

**ronverdonk** · Mar 19 '08, 12:19 PM

Please enclose your posted code in [code] tags (See How to Ask a Question).

This makes it easier for our Experts to read and understand it. Failing to do so creates extra work for the moderators, thus wasting resources, otherwise available to answer the members' questions.

Please use [code] tags in future.

This is not a PHP question, but a JavaScript one.

This thread will be moved to the JS forum.

moderator

**hsriat** · Mar 19 '08, 05:38 PM

[code=javascript]xmlhttp.open("G ET", "ajax.php?i d=" + id + "&action=" + action, true);[/code]

**acoder** · Mar 19 '08, 08:51 PM

Threads merged. Please do not double post your questions.

Moderator.

**vjayis** · Mar 20 '08, 03:41 AM

Originally posted by rpnew

Hi,

What is the error that you are getting??

Regards,
RP

hi Rp.,

when i click on the ajax link("Next") i get an error displaying tht:
Error: Unknown runtime error;

thts it.,

thanks.,
vijay

**acoder** · Mar 20 '08, 12:17 PM

You have an extra double quote in the URL string:

Code:

"url/"ajax.php?id="+id+"&action="+action

instead of

Code:

"url/ajax.php?id="+id+"&action="+action

**vjayis** · Mar 21 '08, 03:29 AM

Originally posted by acoder

You have an extra double quote in the URL string:

Code:

"url/"ajax.php?id="+id+"&action="+action

instead of

Code:

"url/ajax.php?id="+id+"&action="+action

hi

sorry for the mistake.,

i hav written

Code:

"url/ajax.php?id="+id+"&action="+action

[/QUOTE] like this only.,

instead of giving the full link i just typed it inside the quoutes to replace my web link., just to highlight the link.,

I replace my full code one more time.,

Code:

<script type="text/javascript">
var id;
var action;
function httprequest(id,action)
{

var xmlhttp;
try
{
 xmlhttp=new XMLHttpRequest();
}
catch(e)
{
  try
  {
  xmlhttp=new Activexobject("Msxml2.XMLHTTP");
  }
  catch(e)
  { 
    try
	{
    xmlhttp=new Activexobject("MICROSOFT.XMLHTTP")
	}
	catch(e)
	{
	 alert("ur browser doesnot support Ajax");
	 return false;
	}
  }
  
}
xmlhttp.onreadystatechange=function()
{ 
 if(xmlhttp.readyState==4)
 { 
   
   obj = document.getElementById( "ajax" );
   
   obj.innerHTML = xmlhttp.responseText;
   getBufferText();
   
 }
}

xmlhttp.open("GET", "url/ajax.php?id=" + id + "&action=" + action, true);
xmlhttp.send(null);
}

function hidden(id,action)
{
 httprequest(id,action)
}
</script>

[code-php]

<table id="ajax">------Place where i fetch data from another page and display---------
<tr><td><a onclick="hidden ('1','next')">n ext</a></td></tr>
</table>

[/code]
thanks

**acoder** · Mar 21 '08, 04:57 PM

Which line does the error occur on?

**vjayis** · Mar 22 '08, 03:30 AM

Originally posted by acoder

Which line does the error occur on?

Hi

got solution for the problem.,

tried using div tag from the suggestion gave by "gits" in another forum.,

But when the page loads i get an error (only in ie which runs well in firefox)

Error: 'document.getEl ementById(...)' is null or not an object.

can u give me some t ips.,

thanks

**acoder** · Mar 22 '08, 03:46 PM

I assume the error occurs on the following line:

Code:

obj = document.getElementById( "ajax" );

Try using a different ID in case IE has a problem with the "ajax" id.

Failing that, is it possible that you have a test page?

**vjayis** · Mar 24 '08, 09:16 AM

Originally posted by acoder

I assume the error occurs on the following line:

Code:

obj = document.getElementById( "ajax" );

Try using a different ID in case IE has a problem with the "ajax" id.

Failing that, is it possible that you have a test page?

Hi
sorry i couldnt send u a test page.,

Can u tell me whether ajax can be run in ie5 and ie6.,

coz my ajax script is not running in an system which has ie6 installed., i hav tried even by enabling most of the options in browser settings.,

here is my javascript coding

[code=javascript]
function httprequest()
{

var xmlhttp;
try
{
xmlhttp=new XMLHttpRequest( );
}
catch(e)
{
try
{
xmlhttp=new ActiveXObject(" Msxml2.XMLHTTP" );
}
catch(e)
{
try
{
xmlhttp=new ActiveXObject(" MICROSOFT.XMLHT TP")
}
catch(e)
{
alert("ur browser doesnot support Ajax");
return false;
}
}

}
------------------------------
}[/code]

when i click on the ajax link i got an alert message "ur browser doesnot support Ajax" which i hav given in the script.,

Thanks

**acoder** · Mar 24 '08, 06:29 PM

Originally posted by vjayis

Can u tell me whether ajax can be run in ie5 and ie6.,

Yes, it can. You may need to watch the case - see if this link helps.

Error: Unknown runtime error in ie while using ajax

Error: Unknown runtime error in ie while using ajax

Comment

Comment

Comment

Comment

Comment

Comment

Comment

Comment

Comment

Comment

Comment

Comment

Comment

Comment