Using a variable name for the string.replace() regexp

[X l e c t r i c]

Here:

http://bigbangfodder.fileave.com/res/sandr.html

I'm trying to use string.replace( ) for a basic search and replace form
using textarea values as the regexp and replacement values for
string.replace( ).

When I tried to use the textarea variable name for regexp it didn't work
as I thought it would. For example:

string.replace(/variablename/, replacementvari ablename);

This actually searched for variablename instead of the value it
represents. Which actually makes sense. What I did to solve the problem
was this:

var e_v = eval('/' + variablename + '/' + g_b + c_s);

where g_b and c_s are variable names for global and sensitivity
depending upon whether or not checkboxes are checked.

Then I follow that with:

t_ai.value = t_ai.value.repl ace(e_v, t_ar);

t_ai is the variable name for the textarea that holds the text that's
being searched and t_ar is the variable name for the replacement
textarea value.

Is there a way that I can accomplish this without using eval() ?

The text in the textareas and the "Clear Values" button are there as a
convenience for anyone who takes a look to help me, and won't be there
when I'm finished.

Art

[RobG]

Re: Using a variable name for the string.replace( ) regexp

On Mar 2, 12:51 pm, Xlect...@webtv. net (X l e c t r i c) wrote:

Here:
>

http://bigbangfodder.fileave.com/res/sandr.html

>
I'm trying to use string.replace( ) for a basic search and replace form
using textarea values as the regexp and replacement values for
string.replace( ).
>
When I tried to use the textarea variable name for regexp it didn't work
as I thought it would. For example:
>
string.replace(/variablename/, replacementvari ablename);
>
This actually searched for variablename instead of the value it
represents. Which actually makes sense. What I did to solve the problem
was this:
>
var e_v = eval('/' + variablename + '/' + g_b + c_s);

Use RegExp as a constructor:

var e_v = new RegExp(variable name, g_b + c_s);


--
Rob

[X l e c t r i c]

Re: Using a variable name for the string.replace( ) regexp

RobG wrote:

Use RegExp as a constructor:

var e_v = new RegExp(variable name, g_b + c_s);

That's outstanding Rob.

I had tried different versions of the RegExp constructor but they
included the slashes ( / ) and various combinations of quotes, and they
obviously didn't work.

Thank you very much.

Art