javasript problem - submiting

[Bartosz Wegrzyn]

Please look at my code.
I do validation of my form before I submit it.

I want to be able to to press one form button without running validating
script.
I just want to go directly to my php script.

I tried to do this
onclick="docume nt.form1.submit ()" but than the button value is not posted
and my php script is not working.

Also I tried to remove the onSubmit handler on my form and than I add this
to all my 3 buttons that will run with validation.


<input type="button" name="select" value="save" on click="return
check(this);doc ument.form1.sub mit()"It is not working I get error that Java
does not support that object or method.Also the value save is not
submitted.Is there any way to fix this

[Jeff Thies]

Re: javasript problem - submiting

> Please look at my code.[color=blue]
> I do validation of my form before I submit it.[/color]

Do this instead:

<form onsubmit="retur n checkForm()" ...>

Have checkForm return true if all is good and return false if there is
an error.

This will let you use a normal submit button and will let the form
work if javascript is disabled.

Jeff
[color=blue]
>
> I want to be able to to press one form button without running validating
> script.
> I just want to go directly to my php script.
>
> I tried to do this
> onclick="docume nt.form1.submit ()" but than the button value is not posted
> and my php script is not working.
>
> Also I tried to remove the onSubmit handler on my form and than I add this
> to all my 3 buttons that will run with validation.
>
> <input type="button" name="select" value="save" on click="return
> check(this);doc ument.form1.sub mit()"It is not working I get error that Java
> does not support that object or method.Also the value save is not
> submitted.Is there any way to fix this[/color]

[Jeff Thies]

Re: javasript problem - submiting



Jeff Thies wrote:[color=blue]
>[color=green]
> > Please look at my code.
> > I do validation of my form before I submit it.[/color]
>
> Do this instead:
>
> <form onsubmit="retur n checkForm()" ...>[/color]

I've reread your post and I think I misunderstood what you wanted. I
think you want a submit button that bypasses the onsubmit validation

Try this

<form onsubmit="retur n checkForm()" ...>
<input type="submit" value="normal" >
<input type="submit" value="bypass" onclick="bypass ='1'">


var bypass;
function checkForm(){
if(bypass){retu rn true;}
....
normal form check code ...

Jeff

[color=blue]
>
> Have checkForm return true if all is good and return false if there is
> an error.
>
> This will let you use a normal submit button and will let the form
> work if javascript is disabled.
>
> Jeff
>[color=green]
> >
> > I want to be able to to press one form button without running validating
> > script.
> > I just want to go directly to my php script.
> >
> > I tried to do this
> > onclick="docume nt.form1.submit ()" but than the button value is not posted
> > and my php script is not working.
> >
> > Also I tried to remove the onSubmit handler on my form and than I add this
> > to all my 3 buttons that will run with validation.
> >
> > <input type="button" name="select" value="save" on click="return
> > check(this);doc ument.form1.sub mit()"It is not working I get error that Java
> > does not support that object or method.Also the value save is not
> > submitted.Is there any way to fix this[/color][/color]

[Bartosz Wegrzyn]

Re: javasript problem - submiting

I like the idea,but I am having problems with passing the bypass value to
the script.

I have onclick="bypass ='1'"
and in my script I have

var bypass
if (bypass) {return true;}

my function...

shoutnot it be
if (bypass==1) {return true;}

Because this is not working.

Bart,




















































"Jeff Thies" <cyberjeff@spri ntmail.com> wrote in message
news:3F5C03AB.6 7378A69@sprintm ail.com...[color=blue]
>
>
> Jeff Thies wrote:[color=green]
> >[color=darkred]
> > > Please look at my code.
> > > I do validation of my form before I submit it.[/color]
> >
> > Do this instead:
> >
> > <form onsubmit="retur n checkForm()" ...>[/color]
>
> I've reread your post and I think I misunderstood what you wanted. I
> think you want a submit button that bypasses the onsubmit validation
>
> Try this
>
> <form onsubmit="retur n checkForm()" ...>
> <input type="submit" value="normal" >
> <input type="submit" value="bypass" onclick="bypass ='1'">
>
>
> var bypass;
> function checkForm(){
> if(bypass){retu rn true;}
> ...
> normal form check code ...
>
> Jeff
>
>[color=green]
> >
> > Have checkForm return true if all is good and return false if there is
> > an error.
> >
> > This will let you use a normal submit button and will let the form
> > work if javascript is disabled.
> >
> > Jeff
> >[color=darkred]
> > >
> > > I want to be able to to press one form button without running[/color][/color][/color]
validating[color=blue][color=green][color=darkred]
> > > script.
> > > I just want to go directly to my php script.
> > >
> > > I tried to do this
> > > onclick="docume nt.form1.submit ()" but than the button value is not[/color][/color][/color]
posted[color=blue][color=green][color=darkred]
> > > and my php script is not working.
> > >
> > > Also I tried to remove the onSubmit handler on my form and than I add[/color][/color][/color]
this[color=blue][color=green][color=darkred]
> > > to all my 3 buttons that will run with validation.
> > >
> > > <input type="button" name="select" value="save" on click="return
> > > check(this);doc ument.form1.sub mit()"It is not working I get error that[/color][/color][/color]
Java[color=blue][color=green][color=darkred]
> > > does not support that object or method.Also the value save is not
> > > submitted.Is there any way to fix this[/color][/color][/color]

[Jeff Thies]

Re: javasript problem - submiting



Bartosz Wegrzyn wrote:[color=blue]
>
> I like the idea,but I am having problems with passing the bypass value to
> the script.
>
> I have onclick="bypass ='1'"
> and in my script I have
>
> var bypass
> if (bypass) {return true;}
>
> my function...
>
> shoutnot it be
> if (bypass==1) {return true;}[/color]

Either way. 1 is true, 0 or undefined is false.

Here's my little test page:

<html>
<body>
<script type="text/javascript">
var bypass;
function checkForm(){
if(bypass){aler t('go');return true;}else{
alert('no go');return false;
}
}
</script>
<form onsubmit="retur n checkForm()" action="somewhe re.htm">
<input type="submit" value="normal" >
<input type="submit" value="bypass" onclick="bypass ='1'">
</form>
</body>
</html>

Jeff


[color=blue]
>
> Because this is not working.
>
> Bart,
>
> "Jeff Thies" <cyberjeff@spri ntmail.com> wrote in message
> news:3F5C03AB.6 7378A69@sprintm ail.com...[color=green]
> >
> >
> > Jeff Thies wrote:[color=darkred]
> > >
> > > > Please look at my code.
> > > > I do validation of my form before I submit it.
> > >
> > > Do this instead:
> > >
> > > <form onsubmit="retur n checkForm()" ...>[/color]
> >
> > I've reread your post and I think I misunderstood what you wanted. I
> > think you want a submit button that bypasses the onsubmit validation
> >
> > Try this
> >
> > <form onsubmit="retur n checkForm()" ...>
> > <input type="submit" value="normal" >
> > <input type="submit" value="bypass" onclick="bypass ='1'">
> >
> >
> > var bypass;
> > function checkForm(){
> > if(bypass){retu rn true;}
> > ...
> > normal form check code ...
> >
> > Jeff
> >
> >[color=darkred]
> > >
> > > Have checkForm return true if all is good and return false if there is
> > > an error.
> > >
> > > This will let you use a normal submit button and will let the form
> > > work if javascript is disabled.
> > >
> > > Jeff
> > >
> > > >
> > > > I want to be able to to press one form button without running[/color][/color]
> validating[color=green][color=darkred]
> > > > script.
> > > > I just want to go directly to my php script.
> > > >
> > > > I tried to do this
> > > > onclick="docume nt.form1.submit ()" but than the button value is not[/color][/color]
> posted[color=green][color=darkred]
> > > > and my php script is not working.
> > > >
> > > > Also I tried to remove the onSubmit handler on my form and than I add[/color][/color]
> this[color=green][color=darkred]
> > > > to all my 3 buttons that will run with validation.
> > > >
> > > > <input type="button" name="select" value="save" on click="return
> > > > check(this);doc ument.form1.sub mit()"It is not working I get error that[/color][/color]
> Java[color=green][color=darkred]
> > > > does not support that object or method.Also the value save is not
> > > > submitted.Is there any way to fix this[/color][/color][/color]

[Lasse Reichstein Nielsen]

Re: javasript problem - submiting

"Bartosz Wegrzyn" <blwegrzyn@lexo n.ws> writes:
[color=blue]
> I like the idea,but I am having problems with passing the bypass value to
> the script.
>
> I have onclick="bypass ='1'"[/color]

It really should be
onclick="bypass =true;"
No need to use the string '1' to represent true, when there is a perfectly
good boolean value.
[color=blue]
> and in my script I have[/color]
[color=blue]
> var bypass[/color]

The "var bypass" should be outside the function, as a global variable.
You might want to initialize it:
var bypass = false;
It is not important, but it makes the code easier to read (you can see
that it holds a boolean that is initially false).
[color=blue]
> if (bypass) {return true;}[/color]

This should work. The condition of an if statement is converted to a
boolean, and a non-empty string ('1') is converted to true.
The values that are converted to false are
false, null, undefined, "" (empty string), 0, and NaN (not-a-number).
[color=blue]
> my function...
>
> shoutnot it be
> if (bypass==1) {return true;}[/color]

No. If you want to compare to the string, it should be
if (bypass == '1') {return true;}
It is just simpler to use
onclick="bypass = true;"
and then just test
if (bypass) {return true;}
[color=blue]
> Because this is not working.[/color]

If it still isn't workig, try inserting an
alert(bypass)
just before the if statement, and see what value it has.

/L
--
Lasse Reichstein Nielsen - lrn@hotpop.com
Art D'HTML: <URL:http://www.infimum.dk/HTML/randomArtSplit. html>
'Faith without judgement merely degrades the spirit divine.'

[Vjekoslav Begovic]

Re: javasript problem - submiting

"Bartosz Wegrzyn" <blwegrzyn@lexo n.ws> wrote in message
news:IGR6b.2209 1$Ih1.8367612@n ewssrv26.news.p rodigy.com...[color=blue]
> Please look at my code.
> I do validation of my form before I submit it.
>
> I want to be able to to press one form button without running validating
> script.
> I just want to go directly to my php script.[/color]

Try this:

<form method="get" action="whateve r.php" onsubmit="retur n checkForm()">
<input type="submit" value="normal" >
<input type="button" value="bypass" onclick="this.f orm.submit()">
</form>

Vjekoslav

[Bartosz Wegrzyn]

Re: javasript problem - submiting

On Mon, 08 Sep 2003 11:10:48 +0200, Lasse Reichstein Nielsen wrote:
[color=blue]
> "Bartosz Wegrzyn" <blwegrzyn@lexo n.ws> writes:
>[color=green]
>> I like the idea,but I am having problems with passing the bypass value to
>> the script.
>>
>> I have onclick="bypass ='1'"[/color]
>
> It really should be
> onclick="bypass =true;"
> No need to use the string '1' to represent true, when there is a perfectly
> good boolean value.
>[color=green]
>> and in my script I have[/color]
>[color=green]
>> var bypass[/color]
>
> The "var bypass" should be outside the function, as a global variable.
> You might want to initialize it:
> var bypass = false;
> It is not important, but it makes the code easier to read (you can see
> that it holds a boolean that is initially false).
>[color=green]
>> if (bypass) {return true;}[/color]
>
> This should work. The condition of an if statement is converted to a
> boolean, and a non-empty string ('1') is converted to true.
> The values that are converted to false are
> false, null, undefined, "" (empty string), 0, and NaN (not-a-number).
>[color=green]
>> my function...
>>
>> shoutnot it be
>> if (bypass==1) {return true;}[/color]
>
> No. If you want to compare to the string, it should be
> if (bypass == '1') {return true;}
> It is just simpler to use
> onclick="bypass = true;"
> and then just test
> if (bypass) {return true;}
>[color=green]
>> Because this is not working.[/color]
>
> If it still isn't workig, try inserting an
> alert(bypass)
> just before the if statement, and see what value it has.
>
> /L[/color]

Thanks its working.

[Bartosz Wegrzyn]

Re: javasript problem - submiting

On Mon, 08 Sep 2003 07:39:41 +0000, Jeff Thies wrote:
[color=blue]
>
>
> Bartosz Wegrzyn wrote:[color=green]
>>
>> I like the idea,but I am having problems with passing the bypass value to
>> the script.
>>
>> I have onclick="bypass ='1'"
>> and in my script I have
>>
>> var bypass
>> if (bypass) {return true;}
>>
>> my function...
>>
>> shoutnot it be
>> if (bypass==1) {return true;}[/color]
>
> Either way. 1 is true, 0 or undefined is false.
>
> Here's my little test page:
>
> <html>
> <body>
> <script type="text/javascript">
> var bypass;
> function checkForm(){
> if(bypass){aler t('go');return true;}else{
> alert('no go');return false;
> }
> }
> </script>
> <form onsubmit="retur n checkForm()" action="somewhe re.htm">
> <input type="submit" value="normal" >
> <input type="submit" value="bypass" onclick="bypass ='1'">
> </form>
> </body>
> </html>
>
> Jeff
>
>
>[color=green]
>>
>> Because this is not working.
>>
>> Bart,
>>
>> "Jeff Thies" <cyberjeff@spri ntmail.com> wrote in message
>> news:3F5C03AB.6 7378A69@sprintm ail.com...[color=darkred]
>> >
>> >
>> > Jeff Thies wrote:
>> > >
>> > > > Please look at my code.
>> > > > I do validation of my form before I submit it.
>> > >
>> > > Do this instead:
>> > >
>> > > <form onsubmit="retur n checkForm()" ...>
>> >
>> > I've reread your post and I think I misunderstood what you wanted. I
>> > think you want a submit button that bypasses the onsubmit validation
>> >
>> > Try this
>> >
>> > <form onsubmit="retur n checkForm()" ...>
>> > <input type="submit" value="normal" >
>> > <input type="submit" value="bypass" onclick="bypass ='1'">
>> >
>> >
>> > var bypass;
>> > function checkForm(){
>> > if(bypass){retu rn true;}
>> > ...
>> > normal form check code ...
>> >
>> > Jeff
>> >
>> >
>> > >
>> > > Have checkForm return true if all is good and return false if there is
>> > > an error.
>> > >
>> > > This will let you use a normal submit button and will let the form
>> > > work if javascript is disabled.
>> > >
>> > > Jeff
>> > >
>> > > >
>> > > > I want to be able to to press one form button without running[/color]
>> validating[color=darkred]
>> > > > script.
>> > > > I just want to go directly to my php script.
>> > > >
>> > > > I tried to do this
>> > > > onclick="docume nt.form1.submit ()" but than the button value is not[/color]
>> posted[color=darkred]
>> > > > and my php script is not working.
>> > > >
>> > > > Also I tried to remove the onSubmit handler on my form and than I add[/color]
>> this[color=darkred]
>> > > > to all my 3 buttons that will run with validation.
>> > > >
>> > > > <input type="button" name="select" value="save" on click="return
>> > > > check(this);doc ument.form1.sub mit()"It is not working I get error that[/color]
>> Java[color=darkred]
>> > > > does not support that object or method.Also the value save is not
>> > > > submitted.Is there any way to fix this[/color][/color][/color]

Thanks I put the bypass var inside the function.