PHP/AJAX Form Validation - How to?

**gits** · Jul 16 '07, 06:11 PM

hi ...

you may call a validation function onsubmit of your form. when that function returns false the submit is stopped and you may give the hint why ;) ... you only have to compare the values of your inputboxes ... but be aware: you should check that on the server too ... because the script may be modified by the users locally ... so you cannot rely on it in case it is security-relevant ...

try something and post it here in case you have particular problems ...

kind regards

ps: hints are onsubmit of your form, a function that returns true or false, values of your textboxes

**Haitashi** · Jul 16 '07, 06:42 PM

Ok, I see.

I have something like this so far:

Code:

<html>
<head>
<script type="text/javascript">
function validate_email(field,alerttxt)
{
with (field)
{
apos=value.indexOf("@")
dotpos=value.lastIndexOf(".")
if (apos<1||dotpos-apos<2) 
  {alert(alerttxt);return false}
else {return true}
}
}

function validate_form(thisform)
{
with (thisform)
{
if (validate_email(email,"Not a valid e-mail address!")==false)
  {email.focus();return false}
}
}
</script>
</head>

<body>
<form action="submitpage.htm"
onsubmit="return validate_form(this);"
method="post">
Email: <input type="text" name="email" size="30">
<input type="submit" value="Submit"> 
</form>
</body>

</html>

How can I change the warning so that instead of a warning box, the user just gets some text next to the field with the warning information?

**gits** · Jul 16 '07, 06:47 PM

create a div in the position you need and set its innerHTML with the text you want to display ...

you're doing well ;)

kind regards

PHP/AJAX Form Validation - How to?

PHP/AJAX Form Validation - How to?

Comment

Comment

Comment