Regular expression problem...

[buntyindia]

Hi ,

I would like to know the meaning of following regular expressions:

/^((((100)(\\.[0]+)?)|(([0]?\\d{1,2})(\\.[0]+)?))[%]?)$/


/[\\.]/

Please reply

Bunty

[acoder]

Learn about regular expressions here.

[buntyindia]

Learn about regular expressions here.

I already have this link MOD can u please suggest me any community that provide help on Regular expression as this is needed badly

Thanks,
Bunty

[acoder]

What do you not understand about the regular expressions?

I'm assuming that the double backslashes are not supposed to be there - it should be 1 backslash?

A quick look: the first one matches 100 followed by either .0 (at least one 0) or nothing OR a 1-3 digit number followed by either .0 or .00(and possibly more 0s) or nothing. Either of those two could also have a %.

So it would match 100.0, 100.00, 100.0%, 100%, 012.0, 012.0%, 12%, 12, etc.

The second one matches a dot (assuming one backslash).

[acoder]

If you haven't already, you can try out your regular expressions using this tool.

[buntyindia]

What do you not understand about the regular expressions?

I'm assuming that the double backslashes are not supposed to be there - it should be 1 backslash?

A quick look: the first one matches 100 followed by either .0 (at least one 0) or nothing OR a 1-3 digit number followed by either .0 or .00(and possibly more 0s) or nothing. Either of those two could also have a %.

So it would match 100.0, 100.00, 100.0%, 100%, 012.0, 012.0%, 12%, 12, etc.

The second one matches a dot (assuming one backslash).

Thanks Mod it is a Gr8 help...
earlier this string was used to match whether the entered number in a text box is plain number or number with % sign if it is replace it to decimal point means

If entered 6 or 6% convert it to 6.0.

But in case if some one entered 6. (6 with point (.) only) only it should also convert it to 6.0 but it is not converting....

can you suggest any change to this regular expression.....

[acoder]

Thanks Mod it is a Gr8 help...
earlier this string was used to match whether the entered number in a text box is plain number or number with % sign if it is replace it to decimal point means

If entered 6 or 6% convert it to 6.0.

But in case if some one entered 6. (6 with point (.) only) only it should also convert it to 6.0 but it is not converting....

can you suggest any change to this regular expression.....

The regular expression can be used to find a match. To replace, you would use the replace method. Show your code.

[buntyindia]

The regular expression can be used to find a match. To replace, you would use the replace method. Show your code.

Actually we use a framework in which code for replacing any string/number is written in core layer of which we don't have access...we can only use some syntax & change Regular expression...

<validator name="pttrnMtchsStrpRplcVld">
                <constraintData>
                                <localeConstraint name="pattern" bundle="PatternDecode" key="perctAsIntConstrt" />
                                <localeConstraint name="stripRegX" bundle="PatternDecode" key="percntStrip" />
                                <localeConstraint name="replcRegX" bundle="PatternDecode" key="decRepalc" />
                                <localeConstraint name="replcValRegX" bundle="PatternDecode" key="decReplacVal" />
                </constraintData>
                
</validator>

in first line we pass the pattern using which to find the string.
in second line what to strip off
in third line replace expression
in fourth with which value to replace etc

perctAsIntConst rt=/^((((100)(\\.[0]+)?)|(([0]?\\d{1,2})(\\.[0]+)?))[%]?)$/
#Decimal Replace
decReplac=/[\\.]/

#Percent
percntStrip=/[%]/

#Decimal Replace Value
decReplacVal=.

[acoder]

So you want to match 6, 6% and 6. and replace with 6.0

For the 6, you can use \d, but then how many digits can you have? You constrained it to between 1 and 2. The dot and the percent are optional, so we have:

^\d{1,2}(\.|%)?$

[chouhan]

Hi,

Here is a url rewriting problem which I have to resolve through Regular Expression.

http://www.test.com/cart/index.php?main_ page=index&cPat h=56_57

I have to rewrite the above url in the following manner:

http://www.test.com/cart/index-main_page-index-cPath-56-57.php

could anyone help me plz

Regards,
chouhan

[kovik]

URL Parsing through PHP and PCRE