Reg exp not working...

[Kim]

Hello,

I want valid input to be 1 to 9 digits followed by an optional decimal
point, followed by an optional 1 to 4 digits. I think this should
work:

re = /\d{1,9}\.?\d{1, 4}/

The problem I am having is that it is not restricting the number of
digits to the right and left of the decimal point. So my "range" parts
({1,9} and {1,4}) are probably wrong in some way but I cannot figure
out how... I have researched the syntax and this seems to make sense to
me. Please help!

Thanks,

Kim

[Michael Winter]

Re: Reg exp not working...

On 21/10/2005 16:26, Kim wrote:

[snip]
[color=blue]
> re = /\d{1,9}\.?\d{1, 4}/
>
> The problem I am having is that it is not restricting the number of
> digits to the right and left of the decimal point.[/color]

Only the decimal point is optional, not the decimal part (which is the
intent, I assume). It also only needs to match a substring. Additional
characters, including non-numeric ones, can appear before and after the
matched pattern.

/^\d{1,9}(\.\d{1 ,4})?$/

The ^ and $ assertions ensure that the pattern matches characters at the
start and end of the string, respectively. In other words, the entire
string must match the pattern.

[snip]

Hope that helps,
Mike

--
Michael Winter
Prefix subject with [News] before replying by e-mail.

[Kim]

Re: Reg exp not working...

I realized I was missing the second ? after I posted. Thanks so
much!!! That works perfectly! :-)

[Evertjan.]

Re: Reg exp not working...

Kim wrote on 21 okt 2005 in comp.lang.javas cript:
[color=blue]
> I want valid input to be 1 to 9 digits followed by an optional decimal
> point, followed by an optional 1 to 4 digits. I think this should
> work:
>
> re = /\d{1,9}\.?\d{1, 4}/[/color]


result = /\d{1,9}\.?\d{1, 4}/.test(myString)

this would accept 1-9 digits + a optional . + 1 to 4 digits

anyware in a long string.

"qwerty12345678 91234qwerty" would be accepted.
[color=blue]
> The problem I am having is that it is not restricting the number of
> digits to the right and left of the decimal point. So my "range" parts
> ({1,9} and {1,4}) are probably wrong in some way but I cannot figure
> out how... I have researched the syntax and this seems to make sense to
> me. Please help![/color]

Try:

function result(x){
return /^\d{1,9}(\.\d{1 ,4})?$/.test(x)
}

alert(result('1 2')) //true
alert(result('q werty12')) //false
alert(result('1 2.23')) //true
alert(result('1 2.')) //false
alert(result('. 23')) //false
alert(result('0 .23')) //true
alert(result('0 00000000.2300') ) //true ????

This what you want?

=============== =

or without accepting starting (except in 0.23) and final zeros:

function result(x){
return /^(([1-9]\d{0,8})|0)(\.\ d{0,3}[1-9])?$/.test(x)
}

alert(result('1 2')) //true
alert(result('q werty12')) //false
alert(result('1 2.23')) //true
alert(result('1 2.')) //false
alert(result('. 23')) //false
alert(result('0 .23')) //true
alert(result('0 00000000.2300') ) //false !!!!


--
Evertjan.
The Netherlands.
(Replace all crosses with dots in my emailaddress)

[Kim]

Re: Reg exp not working...

I am using: /^\d{1,9}(\.\d{1 ,4})?$/

Thank you for you quick and effective responses!

:-)

Kim