getElementsByTagName('#comment') ?

[X t l a n]

Hi.

I'm trying to get a reference to all comments on particular level of
tree.

lev.getElements ByTagName('#com ment') - this expression dosn't work at
all
lev.getElements ByTagName('!') - this works fine only for IE

I prepared something like:
for (_k=0, _l=lev.childNod es; _k<_l.length; _k++)
if (lev.nodeName== '#comment' || lev.nodeName==' !') ...

and works fine but I cannot see the reason, why script should search in
all elements when getElementsByTa gName might be working quicker. Does
anybody know, how to solve that?


Cheers.

[Martin Honnen]

Re: getElementsByTa gName('#comment ') ?


X t l a n wrote:
[color=blue]
> I'm trying to get a reference to all comments on particular level of tree.
>
> lev.getElements ByTagName('#com ment') - this expression dosn't work at all
> lev.getElements ByTagName('!') - this works fine only for IE[/color]

getElementsByTa gName has that name as you can find element nodes that
way and not comment nodes so the loop below is fine but simply check

[color=blue]
> for (_k=0, _l=lev.childNod es; _k<_l.length; _k++)[/color]

if (lev.nodeType == 8)




--

Martin Honnen

http://JavaScript.FAQTs.com/

[X t l a n]

Re: getElementsByTa gName('#comment ') ?

> way and not comment nodes so the loop below is fine but simply check[color=blue][color=green]
>> for (_k=0, _l=lev.childNod es; _k<_l.length; _k++)[/color]
> if (lev.nodeType == 8)[/color]

Under ie < 6 comment type is always 1 like for normal node that's why I
check it the way like:
if lev.nodeName==' #comment' ||lev.nodeName= ='!')

Thx.