RegExp

[Enzo]

Hi,

I need to create a dynamically pattern match
for validate a number input, first without
decimals and then with 2 or more decimals.

Thanks in advance,

Enzo

[Evertjan.]

Re: RegExp

Enzo wrote on 30 aug 2005 in comp.lang.javas cript:
[color=blue]
> I need to create a dynamically pattern match
> for validate a number input, first without
> decimals and then with 2 or more decimals.[/color]

What do you mean by "dynamicall y"?

What did you try yourself?


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Evertjan.
The Netherlands.
(Replace all crosses with dots in my emailaddress)

[Enzo]

Re: RegExp

Hi Evertjan,

I tried this pattern:

/^-?\d+(\.\d{1,3}) ?$/

for 1 to 3 decimals, but I need to replace
the static values '1' & '3' with variables.

Thanks again,

Enzo

[Evertjan.]

Re: RegExp

Enzo wrote on 30 aug 2005 in comp.lang.javas cript:
[color=blue]
> Hi Evertjan,
>
> I tried this pattern:
>
> /^-?\d+(\.\d{1,3}) ?$/
>
> for 1 to 3 decimals, but I need to replace
> the static values '1' & '3' with variables.[/color]

myTestValue = 1.1234

a = 1
b = 3
myRegex = "^-?\\d+\\.\\d{"+a +","+b+"}?$"
re = new RegExp(myRegex, "");

alert( re.test(myTestV alue) )


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Evertjan.
The Netherlands.
(Replace all crosses with dots in my emailaddress)

[Alvaro G Vicario]

Re: RegExp

*** Enzo wrote/escribió (Tue, 30 Aug 2005 11:17:10 GMT):[color=blue]
> I need to create a dynamically pattern match
> for validate a number input, first without
> decimals and then with 2 or more decimals.[/color]

You can take this a start point:

var my_filter=new Array('foo', 'bar');
eval('var re_filter=/^(' + my_filter.join( '|') + ')$/i;');

--
-- Álvaro G. Vicario - Burgos, Spain
-- http://bits.demogracia.com - Mi sitio sobre programación web
-- Don't e-mail me your questions, post them to the group
--

[Evertjan.]

Re: RegExp

Alvaro G Vicario wrote on 30 aug 2005 in comp.lang.javas cript:
[color=blue]
> *** Enzo wrote/escribió (Tue, 30 Aug 2005 11:17:10 GMT):[color=green]
>> I need to create a dynamically pattern match
>> for validate a number input, first without
>> decimals and then with 2 or more decimals.[/color]
>
> You can take this a start point:
>
> var my_filter=new Array('foo', 'bar');
> eval('var re_filter=/^(' + my_filter.join( '|') + ')$/i;');
>[/color]

Never use eval(),
it is evil and not necessary.

--
Evertjan.
The Netherlands.
(Replace all crosses with dots in my emailaddress)

[Enzo]

Re: RegExp

Gracias Alvaro,

pero como dice Evertjan, eval is 'evil' ;-)

Saludos,

Enzo

[Enzo]

Re: RegExp

Works great! Thanks Evertjan!

Enzo

[Evertjan.]

Re: RegExp

Enzo wrote on 30 aug 2005 in comp.lang.javas cript:
[color=blue]
> pero como dice Evertjan, eval is 'evil' ;-)
>[/color]

Because it is true and has been explained so many times in this NG.

Please see the archive.


--
Evertjan.
The Netherlands.
(Replace all crosses with dots in my emailaddress)

[Dr John Stockton]

Re: RegExp

JRS: In article <1YXQe.3343174$ I96.3853437@tel enews.teleline. es>, dated
Tue, 30 Aug 2005 12:05:17, seen in news:comp.lang. javascript, Enzo
<yuyu@yuyu.co m> posted :
[color=blue]
>I tried this pattern:
>
>/^-?\d+(\.\d{1,3}) ?$/
>
>for 1 to 3 decimals, but I need to replace
>the static values '1' & '3' with variables.[/color]

Unless this is school work, you do not *need* to replace the values,
since you can also use (\.\d+) and test the length of the match.

<URL:http://www.merlyn.demo n.co.uk/js-valid.htm>

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