HTML Form question

[vbMark]

On my form I have a text input box.
There are also radio buttons.

I need to take the value of the input box and the value of the selected
radio button and concatenate them with a plus sign in between.

So if the input box's value is: "Hello"
and the input box's name is name=step1
and the radio button's value is: "David"

I want the output to be:

step1=Hello+Dav id

with the plus sign between them.

How can I do this?

Thanks!

[Grant Wagner]

Re: HTML Form question

"vbMark" <no@email.com > wrote in message
news:Xns95C26EE 0C1775noemailco m@130.133.1.4.. .[color=blue]
> On my form I have a text input box.
> There are also radio buttons.
>
> I need to take the value of the input box and the value of the[/color]
selected[color=blue]
> radio button and concatenate them with a plus sign in between.
>
> So if the input box's value is: "Hello"
> and the input box's name is name=step1
> and the radio button's value is: "David"
>
> I want the output to be:
>
> step1=Hello+Dav id
>
> with the plus sign between them.
>
> How can I do this?[/color]

<form name="myForm">
<input type="text" name="myInput" value="Text"><b r>
<input type="radio" name="myRadio" value="One"> 1<br>
<input type="radio" name="myRadio" value="Two"> 2<br>
<input type="radio" name="myRadio" value="Three"> 3<br>
<input type="button" value="Append input and radio"
onclick="
alert(
myFunction(
this.form.eleme nts['myInput'],
this.form.eleme nts['myRadio']
)
);">
</form>
<script type="text/javascript">
function myFunction(text Input, radioInput) {
var s = textInput.value ;

if ('undefined' == typeof radioInput.leng th) {
// normalize the collection of radio buttons
// into an array if there is only one
radioInput = [ radioInput ];
}

var ii = radioInput.leng th;
while (ii-- > 0) {
if (radioInput[ii].checked) {
return s + '+' + radioInput[ii].value;
}
}
return s;
}
</script>

(inline JavaScript split across multiple lines for readability and to
avoid wordwrap)

--
Grant Wagner <gwagner@agrico reunited.com>
comp.lang.javas cript FAQ - http://jibbering.com/faq