Regular expressions again

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  • Christopher Benson-Manica
    #1

    Regular expressions again

    I must be missing something, but I don't know what...

    alert( source.indexOf( "source") );
    var e3="\/source\/ig";
    source=source.r eplace( e3, "pqrst" );
    alert( source.indexOf( "pqrst") );

    The first alert shows 8937, so the substring exists. Therefore,
    "pqrst" must appear no later than 8937 in source, right? So why in
    the world would I get 9091 for the second alert?

    --
    Christopher Benson-Manica | I *should* know what I'm talking about - if I
    ataru(at)cybers pace.org | don't, I need to know. Flames welcome.
    Tags: None
    • Christopher Benson-Manica
      #2
      Re: Regular expressions again

      Christopher Benson-Manica <ataru@nospam.c yberspace.org> spoke thus:
      [color=blue]
      > I must be missing something, but I don't know what...[/color]

      Just to be sure...

      <html>
      <body>
      <script type="text/javascript">
      var source="abcdsou rcebcdefjkwerjk vawerjbksourcep qrstpqrstpqrst" ;
      alert( source.indexOf( "source") );
      var e3="\/source\/gi";
      source=source.r eplace( e3, "pqrst" );
      alert( source.indexOf( "source") );
      </script>
      </body></html>

      So I guess the problem is those stupid backslashes. They're there to
      make sure the page makes it through the W3C's markup validator. So
      how do I both keep the validator happy and actually get this stupid
      regex replacement to work? TIA...

      --
      Christopher Benson-Manica | I *should* know what I'm talking about - if I
      ataru(at)cybers pace.org | don't, I need to know. Flames welcome.

        Comment

        • Grant Wagner
          #3
          Re: Regular expressions again

          Christopher Benson-Manica wrote:
          [color=blue]
          > I must be missing something, but I don't know what...
          >
          > alert( source.indexOf( "source") );
          > var e3="\/source\/ig";[/color]

          That isn't how you assign a literal regexp. Either use:

          var e3 = /source/ig;

          or use:

          var e3 = new RegExp("source" , "ig");

          Note that in this second case, regular String escape sequences apply. In other
          words:

          var myRegExp = /\d{4}/;
          var myRegExp = new RegExp("\\d{4}" );

          are equivalent.

          --
          Grant Wagner <gwagner@agrico reunited.com>
          comp.lang.javas cript FAQ - http://jibbering.com/faq

            Comment

            • Christopher Benson-Manica
              #4
              Re: Regular expressions again

              Grant Wagner <gwagner@agrico reunited.com> spoke thus:
              [color=blue]
              > var e3 = new RegExp("source" , "ig");[/color]

              Should have thought of it myself; perhaps it's time to call it a
              week... Thank you kindly.

              --
              Christopher Benson-Manica | I *should* know what I'm talking about - if I
              ataru(at)cybers pace.org | don't, I need to know. Flames welcome.

                Comment

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