For those Mathematically inclined

[George Hester]

The idea here is to rotate the eyeball around the border of the circle with the mouse. I have it close but it's not right. Any suggestions? Oh your browser must be able to work with htc. Thanks for any ideas. The script is in the htc.

http://hesterloli.dnsalias.com/more5/dial.asp

http://hesterloli.dnsalias.com/includes/dial.htc

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George Hester
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[Randy Webb]

Re: For those Mathematically inclined

George Hester wrote:
[color=blue]
> The idea here is to rotate the eyeball around the border of the circle
> with the mouse. I have it close but it's not right. Any suggestions?
> Oh your browser must be able to work with htc. Thanks for any ideas.
> The script is in the htc.[/color]

Why not make it an html file, make it work, and then convert it to an htc?
[color=blue]
> http://hesterloli.dnsalias.com/more5/dial.asp
>
> http://hesterloli.dnsalias.com/includes/dial.htc
>[/color]


--
Randy
comp.lang.javas cript FAQ - http://jibbering.com/faq

[George Hester]

Re: For those Mathematically inclined

"Randy Webb" <HikksNotAtHome @aol.com> wrote in message news:BK6dnchdMq QkHMLcRVn-hw@comcast.com. ..[color=blue]
> George Hester wrote:
> [color=green]
> > The idea here is to rotate the eyeball around the border of the circle
> > with the mouse. I have it close but it's not right. Any suggestions?
> > Oh your browser must be able to work with htc. Thanks for any ideas.
> > The script is in the htc.[/color]
>
> Why not make it an html file, make it work, and then convert it to an htc?
> [color=green]
> > http://hesterloli.dnsalias.com/more5/dial.asp
> >
> > http://hesterloli.dnsalias.com/includes/dial.htc
> > [/color]
>
>
> --
> Randy
> comp.lang.javas cript FAQ - http://jibbering.com/faq[/color]

Changing it to a html would not change the mechanics that's involved. I am not having
trouuble with the htc. Thanks though.

George Hester
_______________ _______________ ____

[Randy Webb]

Re: For those Mathematically inclined

George Hester wrote:

<--snip-->
[color=blue]
> Changing it to a html would not change the mechanics that's involved. I am not having
> trouuble with the htc. Thanks though.[/color]

While you are not having trouble with the .htc file, you are limiting
your possible audience of people who may potentially help you. When
having a problem, you want as many people as possible willing to help
you, no?

--
Randy
comp.lang.javas cript FAQ - http://jibbering.com/faq

[George Hester]

Re: For those Mathematically inclined


"Randy Webb" <HikksNotAtHome @aol.com> wrote in message news:nO2dnfJ8K6 OCj_3cRVn-rg@comcast.com. ..[color=blue]
> George Hester wrote:
>
> <--snip-->
> [color=green]
> > Changing it to a html would not change the mechanics that's involved. I am not having
> > trouuble with the htc. Thanks though.[/color]
>
> While you are not having trouble with the .htc file, you are limiting
> your possible audience of people who may potentially help you. When
> having a problem, you want as many people as possible willing to help
> you, no?
>
> --
> Randy
> comp.lang.javas cript FAQ - http://jibbering.com/faq[/color]

Yes I suppose so Randy. Putting this into a html is not as easy as you may think. The image is a VML
and if I put the code for that into a html then I get a lot of crap in the folder where the html
will reside. It's not pretty. Oh for <circle></circle>.

If someone said to you I have a circle on a web page that I would like to have an image
follow the border, would the fact that the questioner implements this in a htc matter?

This htc uses JavaScript. And I know I am letting the y component jump to 0. I am also not able
to keep the y component in a steady state. When dx is negative (mouse left to right) the eyeball does the upper
circumference of the circle. mouse(right to left) the lower half of the circumference.

I believe someone who is well versed in JavaScript can "see" this happening just by looking at code. Which I
provided it is in the htc. Maybe I am wrong about that.

I have an example of using setTimeout to do this. It does it without user intervention. Maybe I can
finagle what they have into what I have. It turns out that what I did is pretty close to
what they have. He uses 2-space to do it f(x,y) whereas I use y=f(x) = sqrt(r^2 + x^2).

--
George Hester
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