How do I open a stream connection?

[Kakatwa Amigo]

Hi...
my code always fail when it reached

 server = (StreamConnectionNotifier)Connector.open(url.toString ());

it gives an error: java.io.IOExcep tion: Can't create Service [General fail]

System.out.println("Setting device..");
            local = LocalDevice.getLocalDevice();
                        if (!local.setDiscoverable (DiscoveryAgent.GIAC)) {
                 
                 throw new IOException("Can't set discoverable mode...");
            }
            StringBuffer url = new StringBuffer ("btspp://");
            url.append ("localhost").append (':');
            url.append (uuid.toString ());
            url.append (";name=code");
            url.append (";authorize=false");
            System.out.println("Opening URL");            
            try{
                server = (StreamConnectionNotifier)Connector.open(url.toString ());
            }catch(Exception e){

I don't know how to make a service in a case like this when I'm setting my device in setDiscoverable ...
I would appreciate some explanations and sample.