Java char data type problem

[Rameshwar Soni]

Can anyone please tell me why i am getting an error in the following code?

class Char_Demo
{
	public static void main(String[] n)
	{
// we all know we can store a character literal like A or //B in an char variable

char c='A';
System.out.println("Character c has" +c);   //output is A
		
	// we can even store the ASCII value for A
		
char c1=65;
System.out.println("Character c1 has" +c1 );//output is A


	//But now i want to store a number as a character		
		
	char c2='5';	// 5 stored as a character	System.out.println("Character c2 has" +c2 );//output is 5

// but when i store a number which has more then 1 digit //i get an compile-time error

char c3='12';		// error....why this error comes
System.out.println("Character c3 has" +c3 );
    }
}

]

[Dominik Przybys]

There is an error because in Java we have char datatype containing only one char. If you want to store more than one char, you have to use String class.

[Rameshwar Soni]

Thanks for the reply........I now have understood my mistake........ ............Tha nks