Issue while calling a method

[mota]

public class Sample 
{
	public int called()
	{
			System.out.println(".....I shouldn't be here.....");
		return 0;
		
	}
	
    public void caller()
	{
		System.out.println("It is supposed to be here -->(" + called() + ")<-- Why isn't it working?\n");
	}
}


public class Test
{
	public static void main(String args[])
	{
		Sample me = new Sample();
		me.caller();
	}
}

And the output would be really weird.. it will be like this:
.....I shouldn't be here.....
It is supposed to be here -->(0)<-- Why isn't it working?

so why is it like this? is this an error or a bug or is it intended? if it was intended, explane how please..

[Amit Kumar M]

Please read this article which talks about how method call works in java.

[Dheeraj Joshi]

You are calling called() from caller() method.

Regards
Dheeraj Joshi

[mota]

Maybe I wasn't clear enough.
yes I know that I called called() by caller().
The problem is that the text from called() was written above the text from caller(). While the returned value (0) was placed in the appropriate please.
I mean shouldn't the text from called() be written inside text from caller()? why is the return value is separated from the text?

Thanks in advance.

[Dheeraj Joshi]

No it won't.

When caller() is called. It tries to print the value. But there is a method called in between and it gets executed (i.e called() method)

Since called() method has a System.out.prin tln(). It prints that first.

Then the call is returned to caller method and finally it displays the text.

caller()
called() --> called being called from caller method

It does the operation. (Basically prints and returns 0) ans control comes back to caller().

Regards
Dheeraj Joshi

[mota]

Thank you for enlighten me with your explanation Dheeraj Joshi. It was really getting into my nerves.

thanks again, really appreciate it!

[Dheeraj Joshi]

Happy to help.

Regards
Dheeraj Joshi