Loops

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  • momotaro
    Contributor
    • Sep 2006
    • 357

    Loops

    how this line of code can know that there is more input needed?:

    Code:
    boolean continueLoop = true;
    the original code is :

    Code:
    public class DivideByZeroWithExceptionHandling
    {
       // demonstrates throwing an exception when a divide-by-zero occurs
       public static int quotient( int numerator, int denominator )
    	  throws ArithmeticException
       {
    	  return numerator / denominator; // possible division by zero
       } // end method quotient
    
       public static void main( String args[] )
       {
    	  Scanner scanner = new Scanner( System.in ); // scanner for input
    	  boolean continueLoop = true; // determines if more input is needed
    
    	  do
    	  {
    		 try // read two numbers and calculate quotient
    		 {
    			System.out.print( "Please enter an integer numerator: " );
    			int numerator = scanner.nextInt();
    			System.out.print( "Please enter an integer denominator: " );
    			int denominator = scanner.nextInt();
    
    			int result = quotient( numerator, denominator );
    			System.out.printf( "\nResult: %d / %d = %d\n", numerator,
    			   denominator, result );
    			continueLoop = false; // input successful; end looping
    		 } // end try
    		 catch ( InputMismatchException inputMismatchException )
    		 {
    			System.err.printf( "\nException: %s\n",
    			   inputMismatchException );
    			scanner.nextLine(); // discard input so user can try again
    			System.out.println(
    			   "You must enter integers. Please try again.\n" );
    		 } // end catch
    		 catch ( ArithmeticException arithmeticException )
    		 {
    			System.err.printf( "\nException: %s\n", arithmeticException );
    			System.out.println(
    			   "Zero is an invalid denominator. Please try again.\n" );
    		 } // end catch
    	  } while ( continueLoop ); // end do...while
       } // end main
    } // end class DivideByZeroWithExceptionHandling
  • momotaro
    Contributor
    • Sep 2006
    • 357

    #2
    ok sorry I figure it out thank you anyway :) !

    Comment

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