java giving 50% chance

[wassssup]

i know math.random can randomly generate numbers, but i want to know is there a way to let the system decides which variable to choose from a and b?
i want to set both can randomly be selected (50 - 50) chance?

[r035198x]

i know math.random can randomly generate numbers, but i want to know is there a way to let the system decides which variable to choose from a and b?
i want to set both can randomly be selected (50 - 50) chance?

Math.random generates numbers between 0.0 and 1.0
Half of that is 0.5.
Ideally then, numbers in [0.0, 0.5) have a 50% chance of getting generated.

[wassssup]

Math.random generates numbers between 0.0 and 1.0
Half of that is 0.5.
Ideally then, numbers in [0.0, 0.5) have a 50% chance of getting generated.

yeah...but is there other way then math.random? just curious..

[r035198x]

yeah...but is there other way then math.random? just curious..

java.util.Rando m ?

[BigDaddyLH]

java.util.Rando m?

Indeed. Method Math.random just uses java.util.Rando m anyway, and the class has a bunch of useful methods. Method Math.random is just leftover from the early API. When you think you need a source of randomness you should check out class Random first.

[drsmooth]

if u use the java.util.Rando m, you could use

[CODE=cpp]Random r = new Random();
int choice = r.nextInt(2);
if(choice==0)
//choice 1
else
//choice b[/CODE]

thats what i would recommend, the nextInt(2); would generate either a 1 or a 0, at what i would assume is a 50-50 chance.

[BigDaddyLH]

if u use the java.util.Rando m, you could use

[CODE=Java]Random r = new Random();
int choice = r.nextInt(2);
if(choice==0)
//choice 1
else
//choice b[/CODE]

thats what i would recommend, the nextInt(2); would generate either a 1 or a 0, at what i would assume is a 50-50 chance.

And if it's a turn-left/turn-right you'd be wanting, there's a method for that in Random. No need to generate 0/1 and then turn it into true/false:
[CODE=Java]if (rnd.nextBoolea n()) {
...
} else {
...
}[/CODE]