delete replicating values from an array[]....

[aswath]

hi dere,
i have a question.
i have an array with replicating values.... al i want to do is
delete all replicating values and store the result in another array.
eg.,
String[] a={1,2,3,3};
String []b;
b should be 1.2.3only...... ..not 1,2,3,3
thanks in advance,
regards,
aswath.n.s
(knowledge is power)

[sukatoa]

hi dere,
i have a question.
i have an array with replicating values.... al i want to do is
delete all replicating values and store the result in another array.
eg.,
String[] a={1,2,3,3};
String []b;
b should be 1.2.3only...... ..not 1,2,3,3
thanks in advance,
regards,
aswath.n.s
(knowledge is power)

What is your question?!

regards,
sukatoa

[r035198x]

hi dere,
i have a question.
i have an array with replicating values.... al i want to do is
delete all replicating values and store the result in another array.
eg.,
String[] a={1,2,3,3};
String []b;
b should be 1.2.3only...... ..not 1,2,3,3
thanks in advance,
regards,
aswath.n.s
(knowledge is power)

... and what have you done so far?

Kind regards

HashSet.

[JosAH]

(knowledge is power)

I don't think so: knowing what to do with your knowledge may give some power,
otherwise you just have to carry that knowledge around in your brain.

kind regards,

Jos

[r035198x]

I don't think so: knowing what to do with your knowledge may give some power,
otherwise you just have to carry that knowledge around in your brain.

kind regards,

Jos

... and to prove that, I wrote some VB.NET code today.(there's a first time for everything).
@Jos surely there's an easier way for that problem?

[JosAH]

... and to prove that, I wrote some VB.NET code today.(there's a first time for everything).
@Jos surely there's an easier way for that problem?

Erm, I didn't mean to say that when you accidentally know something that you
*have* to exercise that knowledge. Some knowledge can better be forgotten ;-)

kind regards,

Jos

ps. you can also iterate from the right and stop when you hit a letter ...

[r035198x]

...

ps. you can also iterate from the right and stop when you hit a letter ...

Yeah I knew that, I just couldn't grasp the syntax for the for loop!!

*hides in a little corner*

[JosAH]

Yeah I knew that, I just couldn't grasp the syntax for the for loop!!

I consider that a little plus on your side.

*hides in a little corner*

No need to, nobody is perfect. Case closed, this is a Java forum after all.

kind regards,

Jos ( <--- knows nooooothing about Basic ;-)

[r035198x]

I consider that a little plus on your side.



No need to, nobody is perfect. Case closed, this is a Java forum after all.

kind regards,

Jos ( <--- knows nooooothing about Basic ;-)

Coming back to the original question then, how would I get this duplicates Snipper to work for primitives as well?


[CODE=java]import java.util.Array s;
import java.util.Colle ction;
import java.util.HashS et;
public class Snipper<E> {
E[] array;
public static void main(String[] args) {
Integer[] x = {4,4,7};
System.out.prin tln(Arrays.toSt ring(new Snipper<Integer >().removeDups( x)));
}
public E[] removeDups(Obje ct o) {
Collection<E> c = null;

if(o instanceof Collection) {
c = (Collection<E>) o;
}
else {
try {
array = (E[])o;
}
catch(ClassCast Exception cCE) {
System.out.prin tln("Not supported");

}
}
if(c != null) {
HashSet<E> s = new HashSet (c);
array = (E[])s.toArray();
}
else if(array != null) {
final HashSet<E> s = new HashSet () {
{
for(E e : array) {
add(e);
}
}
};
array = (E[])s.toArray();
}
return array;
}
}[/CODE]

[lopez]

Coming back to the original question then, how would I get this duplicates Snipper to work for primitives as well?


[CODE=java]import java.util.Array s;
import java.util.Colle ction;
import java.util.HashS et;
public class Snipper<E> {
E[] array;
public static void main(String[] args) {
Integer[] x = {4,4,7};
System.out.prin tln(Arrays.toSt ring(new Snipper<Integer >().removeDups( x)));
}
public E[] removeDups(Obje ct o) {
Collection<E> c = null;

if(o instanceof Collection) {
c = (Collection<E>) o;
}
else {
try {
array = (E[])o;
}
catch(ClassCast Exception cCE) {
System.out.prin tln("Not supported");

}
}
if(c != null) {
HashSet<E> s = new HashSet (c);
array = (E[])s.toArray();
}
else if(array != null) {
final HashSet<E> s = new HashSet () {
{
for(E e : array) {
add(e);
}
}
};
array = (E[])s.toArray();
}
return array;
}
}[/CODE]

come on frds.....
i said knowledge is power not MY knowledge is powerful...
n'way lets drop this issue...
hi r035198x ,
i used ur code and its working fine.....
however i would relly appricate if u could explain me that... i hope i'm not bothering u...
regards,
aswath ns
(knowledge is power)

[r035198x]

come on frds.....
i said knowledge is power not MY knowledge is powerful...
n'way lets drop this issue...
hi r035198x ,
i used ur code and its working fine.....
however i would relly appricate if u could explain me that... i hope i'm not bothering u...
regards,
aswath ns
(knowledge is power)

I didn't think you were going to use it because I thought you had an int[].
Which part do you not understand?

[r035198x]

Hey, are you using two accounts?

[aswath]

Hey, are you using two accounts?

she is my college Colleague.. check her mail id if needed frnd.. i posed from her account...
i cannot get u wen u say<E>.. is that some generic terms r wat.. can u plz help me with that.....
regards

[r035198x]

she is my college Colleague.. check her mail id if needed frnd.. i posed from her account...
i cannot get u wen u say<E>.. is that some generic terms r wat.. can u plz help me with that.....
regards

You can read all about those here.

[prisesh26]

wat happened to this forum..
why the Admin's are very hard in their words.

please understand the other people those who are starter, freshers to this language and selected this forum for help.

why cant the experienced people know and understand this and reply to your
help needed people.

no one knows fully and no one is unknown here...

please dont use hard words which will make the subscribers not to visit again


this forum helped me so much..

so i wrote this reply.

Even though this is not the JAVA RELATED REPLY.


regards!!!
well wisher