Xml comparison using any parsers in java

[ramganes]

Here is one xml file name file1.xml

<?xml version="1.0" encoding="UTF-8" standalone="yes "?>
<ns1:samns ns1:id="1239" xmlns:ns1="http ://blogs.sun.com/teera/ns/samns">
<ns1:firstName> arvind</ns1:firstName>
<ns1:lastName>k rishna</ns1:lastName>
<ns1:address>ch ennai</ns1:address>
</ns1:samns>

Here is the another xml file called file2.xml

<?xml version="1.0" encoding="UTF-8"?>
<customer>
<firstName>sach in</firstName>
<lastName>tendu lkar</lastName>
</customer>

I want to compare these two file1.xml and file2.xml files find out the matching tags in both files.
like <firstName></firstName><last Name></lastName>
get the values from file1.xml and put it in file2.xml tags

sample output:
result3.xml

<?xml version="1.0" encoding="UTF-8"?>
<customer>
<firstName>arav ind</firstName>
<lastName>krish na</lastName>
</customer>

what shout i do for this.. can anyone help me out with this

[ramganes]

am waiting for long time is there anybody to reply?

[r035198x]

am waiting for long time is there anybody to reply?

What have you tried so far? Do you know how to read/parse XML files in Java? JAXP is a good starting point for the googling.

[pronerd]

I want to compare these two file1.xml and file2.xml files find out the matching tags in both files.

I do not think XSL will let you compare files, so you will probably want to google for examples using the DOM and or SAX parsers to create the code to do this.