SEATING CHART java program help?

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  • ccarter45
    New Member
    • Mar 2008
    • 10

    #1

    SEATING CHART java program help?

    I need to write a program that goes through a seating chart row by row and find n consecutive seats in a row. If the seating charts has seats available, it must print out the message saying in what row and what seats. If there are no seats available, it must return the message: "There's no group of seats to satisfy your request." It must also print out the seating chart I need help on how to find the n consecutive seats and find the row and number of the seats. Here's what I have so far:"

    Code:
    import java.util.Scanner;
    
    public class TheaterSeating
    {
      public static void main( String args[] )
      {
        int[][] grid;    // declare 2D array reference variable
        int M = 12;
        int N = 12;
        int K = 4;
        
        grid = new int[M][N]; // create 2D array
        for (int i = 0; i<N; i++)
        {
          for (int j = 0; j< M; j++)
          {
            grid [i][j] = (int)(2*Math.random());
          }
        }    
       System.out.println("The current seating chart is:");
        printSeats(grid, M, N);
      }
       
      public static void printSeats(int seat[][], int N, int M)
      {
        for (int i = 0; i<N; i++)
          {
            for (int j = 0; j< M; j++)
            {
     
              System.out.print(seat[i][j]);
            }
            System.out.println("");
          }
        }
      
    }
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