Java program that adds the numbers between 1 and 1000

[BigDaddyLH]

Does it compile? No it doesn't. Take a look at this:

[CODE=Java]if(300=500+i;)[/CODE]

The if statement should take a boolean expression -- an expression that's true or false. But "300=500+i; " isn't well-formed. For one, "=" means assignment, so that code is trying to assign 500 plus i to the number 300! Also, expression don't involve a semicolon. Semicolons are used to turn simple expressions into statements, so no semicolons are needed to form expressions.

[robert scherer]

so would i do this then


if(i==300) (i==500)

[robert scherer]

if(i==300)
system.outprint ln

[JosAH]

if(i==300)
system.outprint ln

Please don't just try to blindly guess until you've got something right (by accident);
it is never going to work. What is it you're trying to express?

kind regards,

Jos

[robert scherer]

im trying to exclude 300 and 500 from my program


//Sums all the numbers from 1 to 1000
//But excludes the numbers 300 and 500
//

public class Robert1
{
public static void main(String[]ARGS)
{
int sum;
int i;
for(i=1;sum=0;i <1000;i++)
if(

im stuck right here

[trdeepak]

how do i wright a java program that adds the numbers between 1 and 1000 but skips 300 and 500 any help on this matter i would greatly appreciate

thank you

//Try the followin code

package addnumber;

/**
*
* @author Deepak
*/
public class AddNumber {

/**
* @param args the command line arguments
*/
public static void main(String[] args) {
long sum = 0;

for (int i=1; i<10001; i++) {
if (i !=300 && i !=500){ // ignore 300 and 500
sum = (sum + i);
}
}
System.out.prin tln("Sum of number 1 to 1000 excluding 300 and 500 is: " + sum);
// TODO code application logic here
}

}

[Laharl]

We don't spoonfeed code here, trdeepak. We give hints and help, but we do not just give code, with or without an explanation. The idea is to get the OP to understand on his or her own, not to just dump code that can be c/p'd and handed in.

[robert scherer]

i did most of the code all ready look for yourself

[Laharl]

You've got a solid start, it's true. However, you don't have any of the actual code to carry out this task. Look at this tutorial from Sun for a good start on where to go from here. Look at if statements in particular.

[sujansarathi]

how do i wright a java program that adds the numbers between 1 and 1000 but skips 300 and 500 any help on this matter i would greatly appreciate

thank you

Hi Robert

This may help u

[code=java]
public class Add {


public static void main(String[] args) {
long sum = 0;

for (int i=1; i<=1000; i++) {
if(i==300 || i==500){
}
else{
sum = (sum + i);
}
}

System.out.prin tln("Sum of number 1 to 1000 excluding 300 and 500 is: " + sum);
}

}[/code]

[JosAH]

@sujansarathi: we don't spoonfeed code here; read the rules of the game by
clicking the 'Help' link in the top right corner of this page. The OP doesn't learn
anything by copying and pasting boiler plate code. Don't do that anymore.

Since the cat is out of the bag, I propose another solution to the OP; no
explanation though but it implements the hint I gave in my first reply:

[code=java]
public class Add {

public static void main(String[] args) {
long sum = 1000L*1001L/2;

System.out.prin tln("Sum of number 1 to 1000 excluding 300 and 500 is: " + (sum-300-500));
}
}[/code]

kind regards,

Jos (mod)

[karthickkuchanur]

//Try the followin code

package addnumber;

/**
*
* @author Deepak
*/
public class AddNumber {

/**
* @param args the command line arguments
*/
public static void main(String[] args) {
long sum = 0;

for (int i=1; i<10001; i++) {
if (i !=300 && i !=500){ // ignore 300 and 500
sum = (sum + i);
}
}
System.out.prin tln("Sum of number 1 to 1000 excluding 300 and 500 is: " + sum);
// TODO code application logic here
}

}

I think u might be wrongf in this condition
i !=300 && i !=500) any way nothing problem

[dwurmfeld]

how do i wright a java program that adds the numbers between 1 and 1000...

When you have to solve a programming problem, I find it helpful to list out in words what you are trying to do;

• the answer is the sum of numbers 1 to 1000
• except 300 and 500
• somehow, either add the numbers individually
• just do not add 300 and 500
• or figure a loop that will increment the number to add to the answer
• figure out a way to check in the loop if 300 or 500 has come up and do not add them to the answer

So... possible program one: Brute force

answer = 1
answer = answer + 2
answer = answer + 3
.....
answer = answer + 299
// skip 300
answer = answer + 301
.....
answer = answer + 499
// skip 500
answer = answer + 501
... a thousand lines later ...
answer = answer + 1000

// It will work, but kind of dumb eh?

Possible solution two: A Loop of some sort

for (every number between 1 and 1000)

if it is a number I don't want, skip it (300 or 500)
otherwise, answer = answer + the current number

end of loop

// Perhaps an easier approach (at least easier to to type it in)

Possible solution three: look up Karl Friedrich Gauss's answer

• very cool
• no loops
• three steps

Just remember, if you can't write the problem down clearly in words, you don't understand the problem, and most likely, your solution will not work. Also, if your solution seems like a lot of work (like writing a thousand plus lines of code in the brute force approach) then there is probably a better way to solve it.

The Java language has many ways to loop, (while, do-while, for) and many conditional statements, (switch-case, if, if-else). Your job is to learn how to use these statements by putting them in some sort of order (a program) that will solve your problem. Feel free to ask how a particular statement works, but don't be discouraged if the answer is to look it up (we will help you with where to look it up). Just don't expect a solution to your homework, and if you do use a hint you find here, give credit where credit is due; like:

// solution based on help from the Java forum....

[sukatoa]

or (int i=1; i<10001; i++) {
if (i !=300 && i !=500){ // ignore 300 and 500
sum = (sum + i);

the if statement always satisfied until the end of the loop... ;-)