Read this program

[gsreenathreddy]

package Anonymous;

class Base
{
public void m1(){
System.out.prin tln("base m1 called");
}

}


package Anonymous;

class AnonymousTest
{
public static void main(String[] args)
{
Base b=new Base(){
public void m1(){
System.out.prin tln("anonymous m1 called");
}
public void m2(){
System.out.prin tln("anonymous m2 called");
}
{
System.out.prin tln("instane initializer called");
}
};
b.m1();
}
}


Can any body explain abt this program

[r035198x]

1.) Please use code tags when posting code.
2.) Which part do you want explained? Have you run it to see what the output is?

[gsreenathreddy]

[code=java]
package Anonymous;

class Base
{
public void m1(){
System.out.prin tln("base m1 called");
}

}


package Anonymous;

class AnonymousTest
{
public static void main(String[] args)
{
Base b=new Base(){ //explain here
public void m1(){
System.out.prin tln("anonymous m1 called");
}
public void m2(){
System.out.prin tln("anonymous m2 called");
}
{
System.out.prin tln("instane initializer called");
}
};
b.m1();
}
}[/code]

[JosAH]

Just posting the code again isn't going to help you much. Did you compile and
run the code?

kind regards,

Jos

[gsreenathreddy]

Yes,

I had compiled and run the application and got the output as

iinstane initializer called
m1 is called.

[r035198x]

Yes,

I had compiled and run the application and got the output as

iinstane initializer called
m1 is called.

What did you expect as the output?

[gsreenathreddy]

I would like what happens internally

[JosAH]

Yes,

I had compiled and run the application and got the output as

iinstane initializer called
m1 is called.

*Which* m1 is called?

kind regards,

Jos