how to read files

[eyeofsoul]

hello..can anybody give me a guide on how to read any file using java..i am working in encrypting files..any file..can anybody give a hand.

[r035198x]

hello..can anybody give me a guide on how to read any file using java..i am working in encrypting files..any file..can anybody give a hand.

How to read a file depends on the type of the files you are reading.
How you read text files is different from how you read binary files and different from how you would read .pdf files.

[Nepomuk]

hello..can anybody give me a guide on how to read any file using java..i am working in encrypting files..any file..can anybody give a hand.

As you're working on encryption, I guess you will want to read and write the files in binary format. To get you started, this Article should give you a rough idea.

You might however not want to use the Scanner class, as it interprets what it reads, but FileInputStream s and BufferedReaders instead.

Greetings,
Nepomuk

[JosAH]

You might however not want to use the Scanner class, as it interprets what it reads, but FileInputStream s and BufferedReaders instead.

Greetings,
Nepomuk

Readers do quite a bit of interpretation as well; better stick to FileInputStream s
for reading raw bytes.

kind regards,

Jos

[eyeofsoul]

i think i got the idea.first i must convert the file into binary right?!but how do i convert the files into binary?..for example i want to convert a jpeg file into binary.how can it be done?

[saharf]

hello..can anybody give me a guide on how to read any file using java..i am working in encrypting files..any file..can anybody give a hand.

hi. here is a way that you can read the content of a file, but before you should specify your file name
FileInputStream fis = new FileInputStream ("E:/Sahar/source codes/exam.txt");
int num = fis.available() ;
byte b[] = new byte[num];
fis.read(b);
String content = new String(b , 0 , num);
System.out.prin tln("content : "+ content);

in the 1st line, you shud write d name of file u want work on it
in d 2nd line: u r asking to find d number of bytes that can b read from fiel
in d 3rd line: making a byte array with d size of ur file
.......: reading byte by byte of file
.......: making a string to write d result of reading file
.......: and finally writing d result as a string

[JosAH]

i think i got the idea.first i must convert the file into binary right?!but how do i convert the files into binary?..for example i want to convert a jpeg file into binary.how can it be done?

No, that's not it; at the lowest level every file is just a sequence of bytes; it's us,
humans who want to interpret the sequence of bytes, e.g. if all of them represent
printable characters and newline (and/or carriage return) characters, it's us humans
that call such a sequence a 'text file'. If the sequence has some other structure,
defined by us, we might call them jpeg files etc. etc.

A FileInputStream simply reads those bytes from a file and that's the class you
need if you just want read bytes from a file sequentially.

So you don't 'convert a file to binary' because every file already is a binary thing.

kind regards,

Jos

[eyeofsoul]

hi. here is a way that you can read the content of a file, but before you should specify your file name
FileInputStream fis = new FileInputStream ("E:/Sahar/source codes/exam.txt");
int num = fis.available() ;
byte b[] = new byte[num];
fis.read(b);
String content = new String(b , 0 , num);
System.out.prin tln("content : "+ content);

thanks you all for giving me the picture of reading a file,,hehe..fin ally i can read anyfile that i want.hehe..this code really help..