java.lang.ArrayIndexOutOfBoundsException

[oll3i]

i get
Exception in thread "main" java.lang.Array IndexOutOfBound sException: 2
at Producent.main( producent.java: 605)

when i run it from bat

@start "Supply Chain Management-Producer to Queue" run Producent queue1 queue2 queue3 queue4

maybe you will se something i dont see

[code=java]
public static void main(String[] args){



if (args.length < 1 || args.length > 4) {
System.out.prin tln("usage: <destination> <destination> <destination> <destination>") ;
System.exit(1);
}else {Producent producent=new Producent(args[0],args[1],args[2],args[3]);}
/// producent.close ();

}
}
[/code]

thank you

[r035198x]

i get
Exception in thread "main" java.lang.Array IndexOutOfBound sException: 2
at Producent.main( producent.java: 605)

when i run it from bat

@start "Supply Chain Management-Producer to Queue" run Producent queue1 queue2 queue3 queue4

maybe you will se something i dont see

[code=java]
public static void main(String[] args){



if (args.length < 1 || args.length > 4) {
System.out.prin tln("usage: <destination> <destination> <destination> <destination>") ;
System.exit(1);
}else {Producent producent=new Producent(args[0],args[1],args[2],args[3]);}
/// producent.close ();

}
}
[/code]

thank you

The error will occur if args.length is 1, 2, or 3. Change your if condition.

[oll3i]

i changed it to
if (args.length < 1 || args.length > 3)but stiil get the exception

[r035198x]

i changed it to
if (args.length < 1 || args.length > 3)but stiil get the exception

You are complicating things for your self. Don't you just want to run this if you have at least 4 objects in your array.

[blazedaces]

i changed it to
if (args.length < 1 || args.length > 3)but stiil get the exception

Your else statement still tries to call args[0], 1, 2, and 3.

Just think about the following scenarios that go to your else statement:

args.length == 1, it still tries to call args[1],2,3

args.length == 2, it still tries to call args[2],3

args.length == 3, it still tries to call args[3]

only with args.length == 4 or more is it able to call all of these...

You need to add else if's for each of these cases or do only when args.length > 3...

Hope this helped you out,

-blazed

[oll3i]

.... i threw out the if
left only
[code=java]
public static void main(String[] args){




Producent producent=new Producent(args[0],args[1],args[2],args[3]);



}
}
[/code]
and i stil get the exception

thank you

[r035198x]

.... i threw out the if
left only
[code=java]
public static void main(String[] args){




Producent producent=new Producent(args[0],args[1],args[2],args[3]);



}
}
[/code]
and i stil get the exception

thank you

Don't throw away the if. You need it to handle abnormal data.
Use the if(args.length > 3) that has been suggested.

[oll3i]

but why it still throws the exception when i got rid of args.length ?
the exception is in thread main so i shouldn't look somewhere else for it ?

[blazedaces]

but why it still throws the exception when i got rid of args.length ?
the exception is in thread main so i shouldn't look somewhere else for it ?

Dude, refer to my above post. It's hard to be any more clear.

It doesn't have ANYTHING to do with trying to access args.length. IndexArrayOutOf Bounds Exception occurs because you're trying to access an index in the array that is too high or too low (doesn't exist) or could not exist (Out Of Bounds, get it? ) .

Listen, it's not because of args.length, args.length will always just give you the length of the array, like 1, or 2 or 3 or whatever number.

It has to do with the following line of code:

Producent(args[0],args[1],args[2],args[3]);

If you have no if statement it's even worse, what if args.length == 0? What if no args are inputted? Listen, do one of the following things:

Change your if condition to be (args.length > 3) or

Make an else if (args.length == 1), one for (args.length == 2) and one for args.length == 3 where you do different things in each.

Now are you understanding where the problem lies?

I hope this helped, good luck,

-blazed

[JosAH]

but why it still throws the exception when i got rid of args.length ?
the exception is in thread main so i shouldn't look somewhere else for it ?

Your exception isn't thrown in your main method; it is thrown somewhere in the
same thread as the one in which the main method executed. Read the message
carefully: it mentions the method and line number where the exception was
thrown. It most certainly was not in your main method; it happened somewhere
where an array did have at most two elements because index 2 (see message)
was out of the array bounds.

or

alternatively that exception was thrown in the main method itself and you didn't
supply four arguments to your main method (less than three actually because
2 is an out of bound array index.

kind regards,

Jos

[oll3i]

yes it's Producent producent=new Producent(args[0],args[1],args[2],args[3]); causing the exception on line 607
weird
it works fine with 2 parameters
but i need four for the queues

[oll3i]

i bat i have 4 parameters
i checked it to be sure

[JosAH]

yes it's Producent producent=new Producent(args[0],args[1],args[2],args[3]); causing the exception on line 607 it worked fine with 2 parameters

Well, there you have your solution: you should pass four argument to your main()
method if your constructor expects four arguments; simple as that.

kind regards,

Jos

[blazedaces]

Well, there you have your solution: you should pass four argument to your main()
method if your constructor expects four arguments; simple as that.

kind regards,

Jos

He should still have error/exception handling if someone/him inputs less then 4 or maybe more arguments though right? ;)

-blazed

[oll3i]

it must be something wrong in bat file cos when i run it
>java Producent q1 q2 q3 q4 it works and app opens