output file - BufferedWriter

[shana07]

Good day!
Kindly please someone tells me why my program generates same content of output file? They're supposed to have different contents.
Must be something wrong about my codes..help me to figure it out, Thank you very much...

for(int i=0; i < 5; i++)    {        
try { 
    output = new BufferedWriter( new FileWriter(FILENAME + ind + ".txt", true)); 
    output.write(name+ " " + add+ " " + phone + "\n"); 
    output.close(); 
     }catch (IOException e) 
      {
       System.out.println("There was a problem creating/writing to the temp file");
        e.printStackTrace();
      } 
 }

[r035198x]

Good day!
Kindly please someone tells me why my program generates same content of output file? They're supposed to have different contents.
Must be something wrong about my codes..help me to figure it out, Thank you very much...

for(int i=0; i < 5; i++) { 
try { 
output = new BufferedWriter( new FileWriter(FILENAME + ind + ".txt", true)); 
output.write(name+ " " + add+ " " + phone + "\n"); 
output.close(); 
}catch (IOException e) 
{
System.out.println("There was a problem creating/writing to the temp file");
e.printStackTrace();
} 
}

What have you done in your code to make your output different?

[shana07]

What have you done in your code to make your output different?

I put output.close(); outside try..
still the same...

[r035198x]

I put output.close(); outside try..
still the same...

Shana, you are using a for loop to output to the file and the part of code you've posted has nothing to suggest that the output should be different.

[shana07]

Shana, you are using a for loop to output to the file and the part of code you've posted has nothing to suggest that the output should be different.

Ok r035198x..hope you can leave this message for a while.
I need to solve this first, please ...

output.write(number + "\n");           
output.write ("A:" +name);

prints output:
51 A
How to make it go to next line like this:
51
A

[JosAH]

Ok r035198x..hope you can leave this message for a while.
I need to solve this first, please ...

output.write(number + "\n");           
output.write ("A:" +name);

prints output:
51 A
How to make it go to next line like this:
51
A

Wrap a PrintWriter around your BufferedWriter and use two separate println()s
for the fields.

kind regards,

Jos

[shana07]

Wrap a PrintWriter around your BufferedWriter and use two separate println()s
for the fields.

kind regards,

Jos

Got it Josah!
Thank you very much.

[shana07]

Allow me to ask one more question about array syntax please.. please
take a look at codes below: Thank you.

 for(int ind=0; ind < 10; ind += 2)  
        {
             b1 = arrayArgs[ind];
             b2 = arrayArgs[ind+1];         
           
            switch (opcode) 
             {           
                case GCD:       out = b1.gcd(b2).toString();
                break;
                default:        throw new BigAlException("invalid operation");
             }  
       String[] output = {out}; //this part - how to initiliaze out to an output array?  
     }
       System.out.println(output); //so here I can print all of outputs from the array

[JosAH]

Allow me to ask one more question about array syntax please.. please
take a look at codes below: Thank you.

 for(int ind=0; ind < 10; ind += 2)  
        {
             b1 = arrayArgs[ind];
             b2 = arrayArgs[ind+1];         
           
            switch (opcode) 
             {           
                case GCD:       out = b1.gcd(b2).toString();
                break;
                default:        throw new BigAlException("invalid operation");
             }  
       String[] output = {out}; //this part - how to initiliaze out to an output array?  
     }
       System.out.println(output); //so here I can print all of outputs from the array

"out" is an int (I guess), so your array initialization should look like this:

String output= { ""+out };

kind regards,

Jos

[JosAH]

Allow me to ask one more question about array syntax please.. please
take a look at codes below: Thank you.

 for(int ind=0; ind < 10; ind += 2)  
        {
             b1 = arrayArgs[ind];
             b2 = arrayArgs[ind+1];         
           
            switch (opcode) 
             {           
                case GCD:       out = b1.gcd(b2).toString();
                break;
                default:        throw new BigAlException("invalid operation");
             }  
       String[] output = {out}; //this part - how to initiliaze out to an output array?  
     }
       System.out.println(output); //so here I can print all of outputs from the array

"out" is an int (I guess), so your array initialization should look like this:

String output= { ""+out };

The expression ""+out has type String so it can be an element of a String array.

kind regards,

Jos

[shana07]

I am stucked now on how to separate my txt file content. I need to print out them using BufferedWriter method....

I have these data in a txt file:

2 0 groupAStart
2 1 groupAStart //From here
3 2 james
5 3 jun
3 4 groupAfinish
8 5 groupAfinish //Until here - goes to output1.txt
3 6 junk
5 7 junk
2 8 groupAStart //from here
2 9 groupAStart
3 10 jello
5 11 juniady
2 12 groupAfinish
2 13 groupAfinish // Until here - goes to output2.txt
.....
.....
....
I don't know what is the syntax to make it work. As I have done this........ple ase advise me..Thank you.

 for(int i=0; i<=100 ; i++)  
{           
  try
  { 
    BufferedReader inputFIRST = new BufferedReader (new FileReader("first100.txt"));
          
  for(int ind=0; ind<=159451;ind++)
   {
                String[] thelineFRST = lineFRST.split(" ");
                String pos = thelineFRST[0];
                String num = thelineFRST[1];
                String group = thelineFRST[2];                      
            
              if(method.equals(""))  //I am clueless this part
              {
bufferWriter = new BufferedWriter( new FileWriter("OutputFirst" +i + ".txt", true)); 
               bufferWriter.write(pos+ " " +num+ " " + "\n");                  
               bufferWriter.close(); 
              }
          }          
         printWriter.close();   
         inputFIRST.close();              
    ....

Happy Labour Day!

[shana07]

"out" is an int (I guess), so your array initialization should look like this:

String output= { ""+out };

The expression ""+out has type String so it can be an element of a String array.

kind regards,

Jos

Yes, out is an int (BigInteger), and don't you think that it should look like this

String[B][][/B] output= { ""+out };

But then, I still print nothing ....erm do you think it's good idea to initiliaze them in into array? Because my idea is to print all the output one short after finish calculating many input values.

[JosAH]

Yes, out is an int (BigInteger), and don't you think that it should look like this

String[B][][/B] output= { ""+out };

But then, I still print nothing ....erm do you think it's good idea to initiliaze them in into array? Because my idea is to print all the output one short after finish calculating many input values.

My bad, I mistyped my answer (lame excuse: I haven't had my espresso yet).
You want a String array so it can be constructed as you showed above.

This gives you an array with one element in it which is the String representation
of variable 'out'. I apologize for the typo.

kind regards,

Jos

[shana07]

My bad, I mistyped my answer (lame excuse: I haven't had my espresso yet).
You want a String array so it can be constructed as you showed above.

This gives you an array with one element in it which is the String representation
of variable 'out'. I apologize for the typo.

kind regards,

Jos

hihiih..no worries ! I know that was a trick to test me ;)
I'll try again to make it works
Kindly please read my aboved message...I have problem on how to separate file contents.Thanks a bunch...

[JosAH]

Kindly please read my aboved message...I have problem on how to separate file contents.Thanks a bunch...

Basically you have lines; each line contains three strings; when a line contains
a string "groupAStar t" you want to start spooling the rest of the text to an
OutputStream or Writer until a line contains the String groupAEnd; right?
Something like this will get you started:

public void spool(BufferedReader in) throws IOException { // read from this reader
   int fileno= 1; // file number in "output#.txt"
   String line;
   PrintWriter out= null; // if null: don't print anything
   while ((line= in.readLine()) != null) { // while next line available
      if (line.indexOf("groupAStart") >= 0) {
         if (out == null)
            out= makeOutFile(fileno++); // build a PrintWriter
      }
      else if (out != null) {
         out.println(line);
         if (line.indexOf("groupAEnd") >= 0) {
            out.close();
            out= null;
         }
   }
   // let caller close the in stream
}

Note that this little methods needs a couple of other methods, e.g. opening
a PrintWriter for the output given a serial number and it needs a 'driver' method
that opens the BufferedReader, calls this method and closes the reader again.
Instead of sticking all functionality in one big, ugly method better decompose
the problem like I did in this little example.

kind regards,

Jos