Where's the logon password in Apache?

[Peter Chatterton]

I want to use jdb for debugging a servlet.

I'm using Apache/JServ with jdk 1.4 (via Textpad on win2K SP 3).

The 'gospel' I'm using is:
'Start the server manually and record the password for remote debugging
(this is displayed on the console).'
'Start the Java debugger:'
'jdb -host your_host -password the_password'
'You should be able to debug your Java classes now using the jdb
command.'


My problem is that I can't find the password from Apache.
I normally start/restart apache as a windows Service.
If I start it from DOS I get:
'C:\orant9i\Apa che\Apache>apac he -k start'
'Oracle HTTP Server Powered by Apache/1.3.12 (Win32) ApacheJServ/1.1
mod_ssl/2.6.4 OpenSSL/0.9.5a mod_perl/1.24 running...'


I've searched the log, conf & property files but can't find any password.
I've also searched the Apache website for 'jdb' without luck.
I've printed out (and read!) the 'Using Apache with MS Windows' manual.


I did a Google:
--Someone suggested starting Apache using using the -X flag, but I don't
seem to have this option.
--Someone else suggested changing jvm12.conf, but I don't have one.

Thanks,
Peter.

Posted to comp.lang.java and
comp.infosystem s.www.servers.misc

[Peter Chatterton]

Update

I tried the following, just-in-case I don't really need a password,
but it doesn't tell me a lot, and I would appreciate some help:

JDB -sourcepath E:\javaPackages org.apache.jser v.JServServletM anager
C:\orant9i\Apac he\Apache>JDB org.apache.jser v.JServServletM anager
Initializing jdb ...[color=blue]
> run[/color]
run org.apache.jser v.JServServletM anager
Set uncaught java.lang.Throw able
Set deferred uncaught java.lang.Throw able[color=blue]
>[/color]
VM Started:
Exception occurred: java.lang.Class NotFoundExcepti on
(uncaught)"thre ad=main", java.net.URLCla ssLoader$1.run( ), line=199 bci=72

main[1] list
Source file not found: URLClassLoader. java
main[1]

Thanks,
Peter.

"Peter Chatterton" <peter@chattert on.name> wrote in message
news:X8HBb.2050 $aF2.269888@new s20.bellglobal. com...[color=blue]
> I want to use jdb for debugging a servlet.
>
> I'm using Apache/JServ with jdk 1.4 (via Textpad on win2K SP 3).
>
> The 'gospel' I'm using is:
> 'Start the server manually and record the password for remote[/color]
debugging[color=blue]
> (this is displayed on the console).'
> 'Start the Java debugger:'
> 'jdb -host your_host -password the_password'
> 'You should be able to debug your Java classes now using the jdb
> command.'
>
>
> My problem is that I can't find the password from Apache.
> I normally start/restart apache as a windows Service.
> If I start it from DOS I get:
> 'C:\orant9i\Apa che\Apache>apac he -k start'
> 'Oracle HTTP Server Powered by Apache/1.3.12 (Win32) ApacheJServ/1.1
> mod_ssl/2.6.4 OpenSSL/0.9.5a mod_perl/1.24 running...'
>
>
> I've searched the log, conf & property files but can't find any password.
> I've also searched the Apache website for 'jdb' without luck.
> I've printed out (and read!) the 'Using Apache with MS Windows' manual.
>
>
> I did a Google:
> --Someone suggested starting Apache using using the -X flag, but I don't
> seem to have this option.
> --Someone else suggested changing jvm12.conf, but I don't have one.
>
> Thanks,
> Peter.
>
> Posted to comp.lang.java and
> comp.infosystem s.www.servers.misc
>
>[/color]