input characters from a string into an array

[Harry]

Folks
I am trying to input the characters of a string into an array. The array
needs to hold strings, so I need to convert the characters into strings and
then input them into the array. I run into a dereferencing error

StringBuffer buffy = new StringBuffer(st rEntered);
for( i = 0; i < buffy.length(); i++ )
strTemp = (buffy.charAt( i ).toString); //throw dereferencing error in
compile
arrayEntered[ i ] = strTemp

Tried this a number of ways '(buffy.charAt( i ).toString); ' but either
throws exception or compiler cannot understand

Any suggestions would be appreciated.

Thanks
Harry

[cornflux]

Re: input characters from a string into an array

What type/object does charAt() return?


Harry wrote:[color=blue]
> Folks
> I am trying to input the characters of a string into an array. The array
> needs to hold strings, so I need to convert the characters into strings and
> then input them into the array. I run into a dereferencing error
>
> StringBuffer buffy = new StringBuffer(st rEntered);
> for( i = 0; i < buffy.length(); i++ )
> strTemp = (buffy.charAt( i ).toString); //throw dereferencing error in
> compile
> arrayEntered[ i ] = strTemp
>
> Tried this a number of ways '(buffy.charAt( i ).toString); ' but either
> throws exception or compiler cannot understand
>
> Any suggestions would be appreciated.
>
> Thanks
> Harry
>
>
>[/color]

[Josef K]

Re: input characters from a string into an array

"Harry" <mackeyha2@hotm ail.com> skrev i meddelandet
news:0OacneiY3Y Zjx-qiU-KYuQ@comcast.co m...[color=blue]
> Folks
> I am trying to input the characters of a string into an array. The array
> needs to hold strings, so I need to convert the characters into strings[/color]
and[color=blue]
> then input them into the array. I run into a dereferencing error
>
> StringBuffer buffy = new StringBuffer(st rEntered);
> for( i = 0; i < buffy.length(); i++ )
> strTemp = (buffy.charAt( i ).toString); //throw dereferencing error in
> compile
> arrayEntered[ i ] = strTemp
>
> Tried this a number of ways '(buffy.charAt( i ).toString); ' but either
> throws exception or compiler cannot understand
>
> Any suggestions would be appreciated.
>
> Thanks
> Harry
>[/color]

charAt returns a primitive char. There is no such thing as a toString for
primitives. Try this:
strTemp = (new Character(buffy .charAt( i )).toString);
Finally an advice. If you use a JavaIDE you will have access to "code
insight", which will tell you which methods can be used at a certain point
in your code.
/Josef

[@ ya h o o.c o m]

Re: input characters from a string into an array

Try
StringBuffer buffy = new StringBuffer(st rEntered);
for( i = 0; i < buffy.length(); i++ )
strTemp = (buffy.charAt( i ) + "");
arrayEntered[ i ] = strTemp;


[color=blue]
> "Harry" <mackeyha2@hotm ail.com> skrev i meddelandet
> news:0OacneiY3Y Zjx-qiU-KYuQ@comcast.co m...
>[color=green]
>>Folks
>>I am trying to input the characters of a string into an array. The array
>>needs to hold strings, so I need to convert the characters into strings[/color]
>
> and
>[color=green]
>>then input them into the array. I run into a dereferencing error
>>
>>StringBuffe r buffy = new StringBuffer(st rEntered);
>> for( i = 0; i < buffy.length(); i++ )
>> strTemp = (buffy.charAt( i ).toString); //throw dereferencing error in
>>compile
>> arrayEntered[ i ] = strTemp
>>
>>Tried this a number of ways '(buffy.charAt( i ).toString); ' but either
>>throws exception or compiler cannot understand
>>
>>Any suggestions would be appreciated.
>>
>>Thanks
>>Harry
>>[/color]
>
>
> charAt returns a primitive char. There is no such thing as a toString for
> primitives. Try this:
> strTemp = (new Character(buffy .charAt( i )).toString);
> Finally an advice. If you use a JavaIDE you will have access to "code
> insight", which will tell you which methods can be used at a certain point
> in your code.
> /Josef
>
>[/color]