Please solve this query for me.

[Deven Oza]

Hi every one
can anybody solve this problem for me.

What initial values of a and c are required such that the final values of a and b are:

a = 32
b = 4

…

int a,b,c

a = ?
b = 0
c = ?

for( b=0; a<12; b++ )
{
a = (a+a) * c;
}

…


Thank you
Deven

[ManjunathRG]

Hi every one
can anybody solve this problem for me.

What initial values of a and c are required such that the final values of a and b are:

a = 32
b = 4

…

int a,b,c

a = ?
b = 0
c = ?

for( b=0; a<12; b++ )
{
a = (a+a) * c;
}

…


Thank you
Deven

hi devan,
simple logic says that a= c= 1 . But the condition in your for loop has a a<12 condition. So how can the final value for a be 32..?? If the condition a<12 is ignored then a = c =1 gives a = 32 when b =4. :)

[chandu031]

Hi every one
can anybody solve this problem for me.

What initial values of a and c are required such that the final values of a and b are:

a = 32
b = 4

…

int a,b,c

a = ?
b = 0
c = ?

for( b=0; a<12; b++ )
{
a = (a+a) * c;
}

…


Thank you
Deven

Hi,

First of all this is not an Oracle query. But let me answer this for you in good spirit.

Since the final value of b is 4 , there will be 5 iterations
Iteration 1 : a = 2ac
Iteration 2: a = 4 ac^2
Iteration 3 : a = 16 ac^3
Iteration 4 : a = 256 ac^4
Iteration 5 : a = 65536 ac^5

Now assuming that this will be the exit condition you have two equations and two unknowns now:

65536 ac^5 = 32
256 ac^4 < 12

Lets put this in this form:

ac^5 = 1/2048
ac^4 < 3/64

These two equations will give you infinite number of solutions. You can choose any of those answers. For example a = 1/64 and c = 1/2 is one answer and also a = 1/2 and c = 1/4 is another solution..

[MMcCarthy]

This question is being moved to Miscellaneous as no language is specified.

ADMIN

[acfuchs]

Hi!

You can use this start values:
a = 0.125
c = 2

Anton

[jaiminpsoni]

The answer is
a = 2
c = -1