How to fix "No new line at end of file" ?

[Noralyn Nguyen]

Case 1:

import java.util.Scanner;

public class PoD {
	public static void main (String [] args) {
            Scanner in = new Scanner(System.in);
		int number1 = in.nextInt();
		int number2 = in.nextInt();
		int number3 = in.nextInt();
		
	double[] arr = {2,3,4};
        double total = 0;

        for(int i=0; i<arr.length; i++){
        	total = total + arr[i];
        }
        double average = total / arr.length;
	System.out.printf("Average number = %.2f", average);
	}
}

Case 2:

public class average {
  public static void main(String[] args) {
  double[] arr = {16,18,19};
        double total = 0;

        for(int i=0; i<arr.length; i++){
        	total = total + arr[i];
        }
        double average = total / arr.length;
	System.out.printf("Average number = %.3f",average);
		}
}

UNIX DIFF` OF CORRECT OUTPUT AND YOUR OUTPUT

1c1
< Average number = 3.00
\ No newline at end of file
---
> Average number = 17.67
\ No newline at end of file
What does it mean ? How to fix it ?

[dev7060]

Unix doesn't treat a file as a text file if there's no newline at the end of the file. This warning is shown to avoid issues while working with multiple files. Say there are two files. The first one with no newline at the end. On passing both files as arguments, the last line of the first file may add up with the first line of the second file on performing the concatenation. Therefore it's always good to use '\n'/CR/CRLF.

POSIX IEEE standards: https://pubs.opengroup.org/onlinepub...tml#tag_03_206

See my older related answer: https://bytes.com/topic/c/answers/97...le#post3824415

[Ishan Shah]

Simply place a newline that is required at the end of a source file to not mess up things. Here's what happens: The #include preprocessor directive adds the content of the included file to the current file as it is

[dev7060]

And what's the point of copying-and-pasting the text from one of my previous answers when I've already provided the link?