compare 2 strings in structure using function it is giving error: expected ‘;’, ‘,’ o

[jinnejeevansai]

#include<stdio. h>
#include<string .h>
struct div1
{
char a[50];
};
struct div2
{
char b[50];
};
void fun(char p.a[],char q.b[])
{
int i,count=0;
if(strlen(p.a)! =strlen(q.b))
{
printf("n");
}
else
{
for(i=0;i<strle n(p.a);i++)
{
if(p.a[i]==q.b[i])
{
count++;
}
if(count==strle n(p.a))
{
printf("y");
}
else
{
printf("n");
}
}
int main()
{ struct div1 p;
struct div2 q;
scanf("%s",&p.a );
scanf("%s",&q.b );
fun(p.a,q.b);
return 0;
}

[weaknessforcats]

Functions require types or pointers for arguments.

void  fun(char p.a[], char q.b[])

p.a[] is not a type nor is it a pointer.

Change this to:

void  fun(char* p, char* q) etc...

Of course, when you do this you will need to make other changes within the function code.