program to add/ remove entry in host is not working

[pranjalgoenka]

the first part of theprogram is working on adding host but an error is generating again and again that search is not a function of 'ofstream'.

plz help me out

#include <fstream.h>
#include <iostream.h>
#include <string.h>
int main()
{
char site[20],c,d;
ifstream in; ofstream out;
cout<<"press 1 to block website & press 2 to open website";
cin>>d;
switch(d)
{
case 1:
{
cout<<"Enter the Name of the Site to Block \n";
cin>>site;
out.open("C:/Windows/System32/drivers/etc/hosts",ios::app );
if(!out)
cout<<"Either File Not Found or Permission Denied, Run as Admin the EXE of the Program";
else
out<<"127.0.0.1 "<<"\t"<<si te;
out.close();
return 0;
}
case 2:
{
cout<<"Enter the Name of Website to open \n";
cin>>site;
out.open("C:/Windows/System32/drivers/etc/hosts",ios::app );
if(!out)
cout<<"Either File Not Found or Permission Denied, Run as Admin the EXE of the Program";
else
out.replace(out .find(site),sit e.length()," ");
out.close();
return 0;
}
case default:
cout<<"wrong choice dude run exe again";
}return 0;
}

[weaknessforcats]

out.replace(out.find(site),site.length(),"      ");

find and replace are not member functions of an output stream. Output data can't be searched because the data has left the program.

To search you need to have the data in a container and then you can search the container.

If you review the member functions for the ofstream class, you will not see find and replace mentioned.

[donbock]

I don't use C++ so this question may not make sense ...

When you cin into a char, do you get a character value or an integer value? That is, should it be case 1 or case '1' ?

[weaknessforcats]

Case 1 is the integer 1. Case '1' is the integer for the character 1. In the ASCII table '1' is 49. Therefore, case '1' and case 49 are equivalent.

[donbock]

What I meant to ask was...

1. If you cin into a char variable,
2. and if you press the "1" key on the keyboard,
3. does the variable get set to integer value of 1 or character value of '1'?

[weaknessforcats]

cin >> to a char will put 49 in the char (the same as '1').

cin >> to an int will put binary 1 in the int.

The char is supposed to contain ASCII characters. You can out a binary 1 in the char by assignment but you can't do it using a keyboard.

[pranjalgoenka]

thnx for the conversation but i already found the solution