To print the pattern of the following using c/c++

[VaibhavKashyap]

how to print
43
12
for 2X2 matrix and
543
612
789
for a 3X3 matrix

and like the pattern continues the matrix shd hv the numbers of its square

for example as the user gives in 4 and 4

the output should be
16 15 14 13
5 4 3 12
6 1 2 11
7 8 9 10

Thanks in advance
Vaibhav

[Nepomuk]

Hi Vaibhav and welcome to bytes.com!

This sounds very much like a homework question, so we won't give you a solution (as stated in our posting guidelines). We will however happily help you find one yourself. What have you done so far? What have you found out about the problem? Do you understand the pattern they are printed in?

[VaibhavKashyap]

How???

Hi Vaibhav and welcome to bytes.com!

This sounds very much like a homework question, so we won't give you a solution (as stated in our posting guidelines). We will however happily help you find one yourself. What have you done so far? What have you found out about the problem? Do you understand the pattern they are printed in?

Actually I understood the pattern that those are numbers of the square from 1 to x square;;

[Nepomuk]

Yes, they are those numbers. But there's also an order to the numbers; do you understand that order? Why for example is the 2x2 matrix

4 3
1 2

rather than, say

1 2
3 4

?

As soon as you've understood the order, I would probably create a 2D-Array and fill it with the numbers, calculating the position of every number before putting it into the array. For this, I'm sure you'll be using the % and / operators, also you may want to use some method of saving the direction you're currently "moving". (This is only one possible solution, you could calculate the position independently for every number.)

[VaibhavKashyap]

understood

Yes, they are those numbers. But there's also an order to the numbers; do you understand that order? Why for example is the 2x2 matrix

4 3
1 2

rather than, say

1 2
3 4

?

As soon as you've understood the order, I would probably create a 2D-Array and fill it with the numbers, calculating the position of every number before putting it into the array. For this, I'm sure you'll be using the % and / operators, also you may want to use some method of saving the direction you're currently "moving". (This is only one possible solution, you could calculate the position independently for every number.)

ya I understood the pattern but how do I position the numbers

[Nepomuk]

You're welcome. :-)

[VaibhavKashyap]

reply

You're welcome. :-)

hey how do I position the numbers????in 2d array

[Nepomuk]

I take it you're asking how to use a 2d array? If so, here's a very basic example:

#include<stdio.h>

int** array;

int main() {
	array = (int**) malloc(sizeof(int) * 2 * 2);
	array[0] = (int*) malloc(sizeof(int) * 2);
	array[1] = (int*) malloc(sizeof(int) * 2);

	array[0][0] = 4;
	array[0][1] = 3;
	array[1][1] = 2;
	array[1][0] = 1;

	printf("%d %d\n", array[0][0], array[0][1]);
	printf("%d %d\n", array[1][0], array[1][1]);
}

Or did I misunderstand your question?

[donbock]

I suggest specifying a field width in the printf format string to insure your numbers are properly aligned. For example,

     printf("%2d %2d\n", array[0][0], array[0][1]);