how to display this date format : 0x/0y/0z

[1samir]

int d,m,y;
printf("give the date of your birth dd/mm/yyyy \n");
scanf("%2d %2d %4d", &d, &m, &y);
if (y>2000){printf ("the date is : %2d / %2d / %2d ", d, m, y-2000);}
else{printf("th e date is %2d / %2d / %2d ", d, m, y-1900);}

//ex: {13/01/2005
the date is : 13/1/5}
i want 2 dispaly 13/01/05

[whodgson]

Why would you want to repeat an error like m=13?
to provide leading zeros for d and m you could do something like this:

if(d<10 || mm<10)
cout<<"date: "<<'0'<<d<<'/'<<'0'<<mm<<'/'<<yyyy;
else cout<<"date: "<<d<<'/'<<mm<<'/'<<yyyy;

your code for controlling yyyy before 2000 would provide no clue as to century.