How to delete duplicates in characters?

[gujinni]

how to delete duplicates in characters?
output:
string:bnbhhggl k
result:nlk

[whodgson]

string is an array

cout<<string;//prints bnbhhgglk
string.erase(0,1);
cout<<string;//prints nbhhgglk
string.erase(1,5);
cout<<string;//prints nlk

hopefully!

[gujinni]

without using erase??

how about
without
using erase???

what codes do I need to use without using erase or predefined functions???

[weaknessforcats]

Rather than codE, what you need is an algorithm. Then you code the algorithm.

You might:
1) create an array of char big enough so there is one element for each letter..
2) read one character of your string.
3) Look in the array. The letter A has a value 65 so use element 65 for A's.
4) If the array element is blank, store the A there and output the character.
5) If the array element contains 65, then the A you have is a duplicate. Do not output the character.

Repeat all steps until input is processed.

Now start coding.

As a general rule: Only if you can write on paper in your own words what it is you want to do, can you code it.

[whodgson]

In my above post you cannot use string as a name as it is a reserve word. The string would have to be declared with something like string s ="bnbhhgglk" . Clearly this is not the approach you want.

[whodgson]

One possible method would be:
1. create an array (say s) and populate it with lower case alphabet (a to z)
2. create a second array and initialize it with the string holding the duplicates.
3. with two nested loops compare s[0] with s1[0] -> s1[end] and count the number of s[0]`s in s1[].
4. if there is < 1 or > 1 instances of s[0] in s1[] type char(32) into s[0] otherwise do nothing.
5.zero the count and repeat for s[1] which holds 'b'
6.repeat until 'z' is reached.
7.print out the characters that are not spaces in the s[] array.
what follows provides an example of how the nested loops finds which lower case letters are not duplicated in the s1[]array.

for(int i=0;i<27;i++) 
      {count=0;
       for(int j=0;j<len;j++)
        if(s[j]==s1[i])count++;
        for(int j=0;j<len;j++) 
        if(count<1||count>1)s1[i]= char(32);