Error Check.

[jackly84]

ok, I am after looking Every Where and can't seem to find any code on this.

how do i stop a user from Entering in the Same number twice ?

	while((cout<<"Enter Student Number: ")&&(!(cin>>record[n].student_number)||record[n].student_number<0)){
            cout<<"Invalid Input!"<<endl;
            cin.clear();
            cin.ignore(1000,'\n');

For Student ID, i dont want user to be able to Enter the Same Student ID for different names.

[mac11]

If they put in a number you don't want just drop that number and ask for another. It looks like you're kind of half way there.

hints:
- don't try to abuse cin by using ignore and clear just read everything they enter
- the while condition is way too complex, try splitting that work out into the while body and make the condition simple

[jackly84]

My other Error check if to make sure they Enter a Number..

but what if i enter 1232 for one ID, 23232 for the next and then in my 3rd Record enter 1232, how can i tell the User that this is taken ?

[whodgson]

You could enter the number (ID) into a vector or array and then loop through the array to establish if it has an element with the same value.

[jackly84]

I have it going into an Array..
But how do i loop over the array to peak into the array to see if i have or have not enter that ID..

[weaknessforcats]

Write a function.

Call it using the number entered,the address of your array and the number of elements. Have the function return true if the number was found and false otherwise.