Can i have a single template object based on the type given by user?

[Rupal Shah]

Like the functionality i want to achieve is as under: but it will not work. How can i achieve the same functionality?

# include <iostream.h>
# include <conio.h>

template <class T>
class Test
{
	T a;
	public:
		void set()
		{
			cin>>a;
		}
		void display()
		{
			cout<<"A is"<<a<<endl;
		}
};

int main()
{
	int choice;
	cin>>choice;
	if(choice == 1)
	{
		Test<int> obj;
	}
	else if(choice ==2)
	{
		Test<char> obj;

	}
	else
	{
		Test<float> obj;

	}
	obj.set();
	obj.display();
	return 0;
}

[hype261]

I haven't tested this out, but I believe you can solve this problem using an interface class.

using namespace std;

class Interface
{
public:
virtual void set() = 0;
virtual void display() = 0;
};

template<typename T>
class Test : public Interface
{
public:
virtual void set()
{
cin >> a;
}

virtual void display()
{
cout << a;
}
private:
T a;
};

int main()
{
Interface * obj;

int choice;
cin >> choice;

if(choice == 1) 
    { 
        obj = new Test<int>(); 
    } 
    else if(choice ==2) 
    { 
        obj = new Test<char>(); 
  
    } 
    else 
    { 
        obj = new Test<float>; 
  
    } 
    obj.set(); 
    obj.display(); 
    delete obj;
    return 0;
}