Why do i have to assign this iterator pointer to a variable before i can use it?

[Liam Kurmos]

im using g++ on ubuntu 10.10

i have a pointer to a vector of pointers to objects and i want to call a method on each of those objects.
oc->features is defined as:

vector<Feature* >* features;

i have to do:

vector<Feature*>::iterator it;
    for (it=oc->features->begin();it!=oc->features->end();it++){
        
        Feature* a=*(it);
        int score=a->scoreFeature(view);
}

this works, but if i try to use the itterator directly, as in:

        int score=*(it)->scoreFeature(view);

I get the following compile error:

ViewEvaluator.c pp:48: error: request for member ‘scoreFeat ure’ in ‘* it.__gnu_cxx::_ _normal_iterato r<_Iterator, _Container>::op erator-> [with _Iterator = Feature**, _Container = std::vector<Fea ture*, std::allocator< Feature*> >]()’, which is of non-class type ‘Feature*’
//make[2]: *** [CMakeFiles/testOVAS.dir/ViewEvaluator.c pp.o] Error 1
//make[1]: *** [CMakeFiles/testOVAS.dir/all] Error 2

non-class type Feature* ?? i dont get it...

can anyone shed light on what might be happening here?

incidentally i thought it could be something to do with having a pointer to a container and using an itterator on it (at first i tried dereferencing that didnt work). I then realised that i have another example in my code using a pointer to vector and the analogous code works.

[Banfa]

Try this

int score = (*it)->scoreFeature(view);

to override the default operator precedence so that it is dereferenced with * before being deferenced with ->

[Liam Kurmos]

:D thanks Banfa!

it was one of those bugs where i just could see the obvious!