help formulating strcmp calls

[tomerkid]

Hello every body i am new to this community and new to proggraming at all i would like to get some help with a strcmp command which i have promlems with.
well take a look at what i have and what i am try to reach:

void Q_3()
{
	char p[4]="yes";/i dont know if "yes" "no" is what i should do
	char j[4]="no";
	while( !strcmp(* "p",* "j"));//this is ofcoruse wrong and i dont know what should i do to make it right
	{
		printf("your name is ***?\n");
		scanf("%s",&p,j);//i want the answears to be yes or no only
		if(!strcmp("p"))//if its yes 
		{
			printf("hi *** i am glad to see you\n");
		}
		else if (j == !strcmp("j"))//if its no
			{
				printf("if you are not *** i dont wish to speak to you\n");
			}
		else//and here a restart for the while since its not one of the options:yes or no
			{
				printf("please answer with yes or no only!\n");
			}
	}
}

[code green]

strcmp takes 2 parameters and returns zero when they match.
Not sure what you are trying here

if(!strcmp("p"))//

Doesn't seem to make sense.
But here

if (j == !strcmp("j"))//

I think you mean

if(!strcmp("j",j))//

It may help if you explain what you are trying to do

[tomerkid]

strcmp takes 2 parameters and returns zero when they match.
Not sure what you are trying here

if(!strcmp("p"))//

Doesn't seem to make sense.
But here

if (j == !strcmp("j"))//

I think you mean

if(!strcmp("j",j))//

It may help if you explain what you are trying to do

ok let me tell you exactly what i am trying to do.

void Q_2()
{
	char x[5]="0";
	while((x[0]!= 'y' && x[1] != 'e' && x[2]!= 's') && (x[0]!= 'n' && x[1]!= 'o'))
	{
		printf("your name is ***?\n");
		scanf("%s",&x);
		if(x[0]== 'y' && x[1] == 'e' && x[2]== 's')
		{
			printf("hi *** i am glad to see you\n");
		}
		else if (x[0]== 'n' && x[1]=='o')
			{
				printf("if you are not ** i dont wish to speak to you\n");
			}
		else
			{
				printf("please answer with yes or no only!\n");
			}
	}
	 Q_3();
}

ok i want to do the same thing as that with strcmp is it clear enought now? if not tell me ill be even more spesific
(and as you can see this i have created the same program in 3 diffrent ways i am looking for the fast and better way)

[code green]

I'm sorry but I do not have time to analyse code to 'work out' your intention.

Posting code is good but that is not an explanation.
Can we have a little more than

ok i want to do the same thing as that with strcmp is it clear enought now

[tomerkid]

ok so in the code i defind a string with 5 slots called x, than i gave a while condition, as long as the first2/3 slots in the string are != y,e,s or n,o the loop will keep going ,now i scanf the x'if x == yes it will print some thing if x==no it will print something else.now if it isnt yes or no the condition in the while will stay as it is so it will loop once more untill x will be changed into yes or no. so in this case i did it with 1 string,now i want to do the same thing as that with strcmp by comapring 2 strings

[weaknessforcats]

while( !strcmp(* "p",* "j"));//this is ofcoruse wrong and i dont know what should i do to make it right 
    {

p and j are strings. Strings are char arrays. The name of an array is the address of element 0. Therefore p and j are pointers to char. strcmp arguments are pointers to char. So..

while( !strcmp(p,j));//this is ofcoruse wrong and i dont know what should i do to make it right 
    {

there's no need to dereference p and j. Objviously your compiler knows that and that's why you got the error.

There's also no need to put quotes around p and j because they are variables.

[tomerkid]

nvm every thing is good