C++ Array Question

[zamaam0728]

I am trying to take the following instructions and make it a working code. The instructions were to use appropriate data types, and all dara types are represented as either numeric or string.

start
string name
string address
num item
num quantity
num price
num SIZE = 6
num VALID_ITEM [SIZE] = 106, 108, 307, 405, 457, 688
num VALID_ITEM_PRIC E [SIZE] = 0.59, 0.99, 4.50, 15.99, 17.50, 39.00
num sub
string foundIt = “N”
string MSG_YES = “Item available”
string MSG_NO = “Item not found”
get name, address, item, quantity
sub = 0
while sub < SIZE
if item = VALID_ITEM [sub] then
foundIt = “Y”
price = VALID_ITEM_PRIC E [sub]
endif
sub = sub + 1
endwhile
if foundIt = “Y” then
print MSG_YES
print quantity, “ at “ , price, “ each”
print “Total “, quantity * price
else
print MSG_NO
endif
stop

My code...

#include <iostream>
#include <string>

using std::cout;
using std::cin;
using std::endl;
using std::string;


int main()
{
	//declare variables and arrays
	string name = "";
	string address = "";
	int item = 0;
	int quantity = 0;
	double price = 0.00;
	const int SIZE = 6;
	int VALID_ITEM[SIZE] = {106, 108, 307, 405, 457, 688};
	double VALID_ITEM_PRICE[SIZE] = {0.59, 0.99, 4.50, 15.99, 17.50, 39.00};
	int sub;
	string foundIt = "N";
	string MSG_YES = "Item available";
	string MSG_NO = "Item not found";
	
	getline (cin, name);
	getline (cin, address);
	

	sub = 0;

	while (sub < SIZE)
	{
		if (item = VALID_ITEM[sub])
		{
			foundIt = "Y";
			price = VALID_ITEM_PRICE[sub];
		}	//end if

		sub = sub + 1;

		// end while

		if (foundIt = "Y")
		{
			cout << MSG_YES <<;
			cout << quantity << "at " << price << " each"
				 << "Total " << quantity * price;
		}
		else 
			cout << MSG_NO << endl;
	}	//end if

}	//end main function

I have two errors:

references line 44 - error C2451: conditional expression of type 'std::basic_str ing<_Elem,_Trai ts,_Ax>' is illegal
1> with
1> [
1> _Elem=char,
1> _Traits=std::ch ar_traits<char> ,
1> _Ax=std::alloca tor<char>
1> ]
1> No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called
references line 46 - error C2059: syntax error : ';'

I'm sure it's something simple, but I can not see it. Any help would be appreciated.

Thanks!

[whodgson]

The while loop seems to be missing a closing brace

[akdemirc]

you are using = instead of == in both if statements,
if (item = VALID_ITEM[sub])
if (foundIt = "Y")

and the statement may also cause error because of the extra << operator at the end

cout << MSG_YES <<;