I cant figure out why my program is crashing. Please Help!!!

[dicky2141]

#include <stdio.h> 
#include <stdlib.h>

void separate(int *first, int *second, int *third);

int main() { 

	int number;
	int A, B, C;	
	
	printf("Enter a positive integer value to be evaluated: ");
	scanf(" %d", &number);
	
	A = number + 0;
	B = number + 0;
	C = number + 0;
	
	printf("\nThe integer value you've chosen is %d\n\n", number);
	
	separate(&A, &B, &C);
	
	printf("The value of A is %d\n\n", A);
	printf("The value of B is %d\n\n", B);
	printf("The value of C is %d\n\n", C);
	
		system("pause");
  
    return 0; 
    
} 

void separate(int *first, int *second, int *third) {
	
	int i, j;
	int input, sum = 0, total_sum = 0;
  
	if (*first % 7 == 0 || *first % 11 == 0 || *first % 13 == 0) {
		*first = 1;
	}
	else {
		*first = 0;
	}
	
	
	for (i = *third; i > 1; i--) {
		if (*third % i == 0) {
			*third = 0;
		}
		else *third = 1;
	} 
	
// The problem is somewhere for here on
//Im trying to add the digits of my imputed variable and return them to my main
//function.	
	for (input = *second; input <= 1000; input++) {
		sum = 0;
		
		for (j=0; j<4; j++) {
		sum = sum + (input / (j*10))%(10) ;
		}
		
		total_sum = total_sum + sum;
	}
	
	*second = total_sum;

}

[kiruthikaU]

The problem in your code is ,

for (input = *second; input <= 1000; input++) {
sum = 0;
for (j=0; j<=4; j++) {
sum = sum + (input / (j*10))%(10) ;
}

In the inner for loop j value starts from zero.
And inside the loop you are performing the operation,
sum = sum + (input / (j*10))%(10) ;
If j value is zero j*10 will be (0*10=>0).
So it will give divide by zero error (i.e) floating point exception.

So you start the j value from one .