Not getting requierd output in C

[amarniit]

I need to get this out put but i am noit getting please help me...... i need its coding


1
01
101
0101
10101
010101
1010101



What i have write it is ............... ......
#include<stdio. h>
#include<conio. h>
void main ()
{
int i,j,limit=10,n= 1;
for(i=1;i<=limi t;i=i+2)
{
for(j=1;j<=i;j+ +)
{
if(n==1)
{
printf("%d",n);
n=0;
}
else
{
printf("%d",n);
n=1;
}
}
printf("\n\n");
}
getch();
clrscr();
}




output of this
1
010
10101
0101010
101010101
but i need this

1
01
101
0101
10101
010101
1010101

[weaknessforcats]

I can't give you the code. All I can do is help you out where you are stuck.

What you need here is a loop and a variable initialized to 1.
Inside that loop you display a variable as many times as the loop counter. That is, when the loop counter is 3 you display the variable 3 times.

After you display the variable, check its value. If it is 1 set it to 0 and if it is 0 set it to 1 for the next display.

[whodgson]

To marginally elucidate on the above:
If you could employ C++ strings you could manipulate them quite simply as follows
If s1="You are a big brute" and s2="and so am I" then if s3=s1+s2 s3 would read "You are a big brute and so am i"
In the context of this problem:
If s0='0' and s1='1' then cout<< s1 prints 1
if s2=s0+s1 cout<<s2 prints 01
if s3 =s1+s2 cout<<s3 prints 101
if s4=s0+s3 cout<<s4 prints 0101
if s5........and so on.
If the above was in the body of a for loop and 'i' cold be made to echo the desired s index s[i] would be assigned the value of s0 or s1+ s[i-1]
Then the only problem left would be how to identify which of the alternating s0 or s1 is to be used.
This could be arranged by declaring (say) flag = 1 above the for loop and towards the end of the for loop body a statement such as if(flag==1)flag ==0 else flag ==1.
Now s0 and s1 become s[flag] being equal to either 0 or 1.
comprenez vous?

[abghosh]

Run this loop:
For(i = 1; i <= Limit; i++)
for(j = 0; j < i; j++)
printf("%d", (i - j) % 2);
printf("\n");
}

Hope this help.

[whodgson]

It might save a lot of angst if you ignore #3 above.
Instead use:
getline(cin ,s) to store say(30) 1010101...`s in s.
or you can generate s with a for loop body containing if(i%2==0)cout< <1;else cout<<0.
s now holds a string (30) 1010101`s.
if you cout<<s you get 101010101010101 010101010101010 .
if you call s.length you get 30
If you use a for loop with condition i<s.length/2 with cout<<substr(i, i+1) in its body
you get:
1
01
101
0101 etc
much less agro.