i have a byte array question

[djones]

I have a byte array that contains a string like 1c1ba2... etc
I would like to print out 5 digits. so for example:

1c = 28
1b = 27
a2 = 162

my output needs to be five digits long so 28271.

I thought about using printf but it seems like when i use it it reports the count
its shows 1 more than there should be

so 1b = 27 but printf report 3. does printf do some kind of padding?
the reason i was looking at counts was to limit my output to 5. I am not sure how else i can do this.

the goal is to print 5 digits out of that byte array.

thank you for your help.

[whodgson]

You have just about solved it.
within a while loop:
1. Combine each successive pair of array elements into a hex integer format and convert that format to decimal. dec_int == this value.
2. Load each to a new array.
Within a loop:
3. Print these values out making sure that if the first value >99, the second value <99 by dividing by 10 or 100, Use a counting variable to ensure that the number of digits in each combination does not exceed 5.

[MrPickle]

I believe the extra character you are seeing is the null terminator '\0'. This is to signify the end of the string.