Ok, I have an if, and the user enters a value outside of the range.....

[abueno]

Ok, I have an if statement, and the user enters a value outside of the range....
say:

int sco; //Variable used for score.

if(sco< 0 || sco > 100)
{
cout<<"Error, You have to enter on the range 0-100\n";
// I want to be able to subtract the last input from the total
// without affect the other valid amounts.
// So, I was thinking in:

ave--;
scomax=-sco; // This is wrong because makes my score to zero, and
in the average variable, instead of subtract 1, subtract 2.


}

else

ave++;

scomax+=sco;
total=comax/ave; // This formula is right when is a valid input, but my negative formula is bad.



// Thank's 4 the comments.

[Banfa]

If sco is out of range then don't include it into ave and scomax, then you don't have to try and subtract it which is hard (if not impossible).

[abueno]

Thank you Banfa,

I will try to assign different name variables, to see if that helps....and I will let sco, only for the valid input.

[whodgson]

Consider the following which rejects invalid input
while(sco is outside required range)
{
//do stuff here
}