find even or odd in array

[AsHantoosH]

#include<stdio. h>

main() {

int a;

printf("Enter a: \n");

scanf("%d", &a);


if (a % 2 == 0) {

printf("The given number is EVEN");

} else {

printf("The given number is ODD");

}

}

the above program find the even or odd but how can i find multiple of 2 for array of 100 elemens

[scruggsy]

#include<stdio. h>
the above program find the even or odd but how can i find multiple of 2 for array of 100 elemens

Any even number is a multiple of 2. No odd number is. So it looks like you already have most of the code to do this, you just need to do it inside a loop inspecting the elements of your array one at a time. If that's the part you're having trouble with, post what you've tried.

As a somewhat useless aside, another way to test if an integer is odd or even:

if (a & 1)  // odd
else   // even

[donbock]

the above program find the even or odd but how can i find multiple of 2 for array of 100 elemens

By "multiple of 2", do you mean "even" (2, 4, 6, 8, 10, ...) or do you mean "power of two" (2, 4, 8, 16, 32, ...)?

[AsHantoosH]

multiple of 2

i mean multiple of 2 (2,4,6)

[Meetee]

In your even number logic you can extends the logic for the multiplicity of 2 as every even number except 0. So modify your logic accordingly.

Regards

[scruggsy]

In your even number logic you can extends the logic for the multiplicity of 2 as every even number except 0. So modify your logic accordingly.

Regards

Not to be nitpicky (or rather, to be very nitpicky :p) but zero is a multiple of all numbers but a factor of none. Negative even numbers are also multiples of 2. Whether either applies in this case depends on the problem statement I guess - OP doesn't specify.

[rahulthapar07]

[ incorrect spoonfeeding code deleted ]

Jos (moderator)