Finding all open windows

[MrPickle]

I am trying to get all open windows on windows. I have looked around and seen that I should use EnumWindows and EnumWindowsProc so I whipped up this code to test it but it tells me there's 300-400 windows open, and I only have about 5?

#include <windows.h>
#include <iostream>

int i;

BOOL CALLBACK EnumWindowsProc(HWND hWnd, LPARAM lParam);

int main(int argc, char** argv) {
	std::cout << "Finding all open windows\n";
	if(EnumWindows(EnumWindowsProc, 0)) {
		std::cout << i << " windows are open\nCall was successful...\n" << std::endl;
		std::cin.get();
	} else {
		std::cout << "Call was unsuccessful...\n" << std::endl;
		std::cin.get();
	}
	
	return 0;
}

BOOL CALLBACK EnumWindowsProc(HWND hWnd, LPARAM lParam) {
	i++;
	return true;
}

[donbock]

Caveat: I'm not a Windows programmer; and I've never used EnumWindows.

1. I suggest setting variable "i" to zero just before calling EnumWindows. It won't fix your problem, but it is a good habit to get into.

2. Could EnumWindows be revisiting the same windows? The way to check that is to accumulate a list of the window handles passed to EnumWindowProc (hWnd) and check if there are any duplicates.

[MrPickle]

After adding the check, I think it may be getting hidden programs too because outputting the program's text gives allot of blanks and things like my laptop's battery life.

Thanks :)