Passing char[][] as argument

[krreks]

I ended up solving my problem with the following piece of code.

char * fillFileArr(char * buf, int num, int maxLen) {
	char * arr = (char *)malloc(num*(maxLen+1));

	int word=0, wordPos=0, bufferPos=0;
	while(word<num && buf[bufferPos]!='\0') {
		if(buf[bufferPos]=='\n') {
			arr[(word*(maxLen+1))+wordPos] = '\0';
			
			word++;
			wordPos=0;
		} else {
			arr[(word*(maxLen+1))+wordPos++] = buf[bufferPos];
		}
		bufferPos++;
	}
	
	return arr;
}

void printFileArr(char * files, int num, int maxLen, int withIndex, int indexStart) {
	int i, index=indexStart;
	for(i=0; i<num; i++) {
		if(withIndex==1)
			printf("! [%2d] ", index++);
		else
			printf("! ");
		printf("%s\n", files+((maxLen+1)*i));
	}
}

char * getFromFileArr(char * arr, int maxLen, int wantedIndex) {
	return (arr+((maxLen+1)*wantedIndex));
}

[weaknessforcats]

The correct code for allocating a 2D array is:

char (* arr)[maxLen+8] = malloc(num*(maxLen+1));

Your function should have had a char (*)[maxLen+8] argument plus one argument for the number of maxLen+8 arrays.

Read this: http://bytes.com/forum/thread772412.html.