Convert long into ASCII Char[]

[Jcan]

hi

I have a long variable:

long id = 0x0457;

which in decimal is 1111

I need to convert id into a char array with its ascii values.

e.g

char arr[4];

arr[0] = '1';
arr[1] = '1';
arr[2] = '1';
arr[3] = '1';

thanks

[Banfa]

Try sprintf, or itoa although the latter function (itoa) while support by several compilers is actually non-standard and I would say may well suffer from re-entrancy issues since it returns a char * to a presumably static buffer.

[weaknessforcats]

Use a common algorithm.

This 1111 is really

1 *1000 + 1 * 100 + 1 * 10 +1.

To see how many 100's there are you

1111/100

That gives the number of 100's. Now to get the digit in the 100's position you:

(1111/100) %10

Now you have a value between 0 and 9. It is an integer value. For a string you have to convert this to an ASCII char.

(1111/100) %10 +'0'


So, constuct a loop so you divide by 1000 then by 100 then by 10 etc and append the result to your string. When your divisor is 0, you are done.