explain a prototype of function

[kalar]

Hello!!!
I have to write a function and they are giving me the prototype of the function, but i don't understand what arguments takes.
the prototype is:

coroutine *co_start(void (*body) (void*), void *attr);

can you explain me what arguments take this function and what returns?
I am really confused.

[sicarie]

Can you post your best guess to that? I would recommend breaking it down into parts:

1) what does the function return?
2) what are parameters passed?
3) what types are the parameters being passed?

You can also google search for help.

[kalar]

coroutine *co_start(void (*body) (void*), void *attr);

coroutine *co_start . This means that i should make a function co_start that returns a pointer to coroutine.

void (*body) (void*) is one of the arguments of the function.This argument is a pointer to a function body.This function takes as argument a pointer to void.

the second argument void *attr of the function co_start is a pointer to void.
Right???

[JosAH]

coroutine *co_start(void (*body) (void*), void *attr);

coroutine *co_start . This means that i should make a function co_start that returns a pointer to coroutine.

void (*body) (void*) is one of the arguments of the function.This argument is a pointer to a function body.This function takes as argument a pointer to void.

... and that function returns nothing (void).

the second argument void *attr of the function co_start is a pointer to void.
Right???

Right.

kind regards,

Jos