debug message in a template class

[thomas]

template <class T>
class BufferQueue{
public:
int BufferQueue<T>: :pushToQueue(T pkt, int timeout);
}

template<class T>
int BufferQueue<T>: :pushToQueue(T pkt, ACE_Time_Value *timeout){
cout<<"in pushToQueue"<<e ndl; --------Line p
return 0;
}

Suppose I have two instances BufferQueue<A_a , BufferQueue<B_b ;
I want to know which instance I'm in by printing some debug messages
out in Line p
like
"in pushToQueue of A", etc.

How can I tell the compiler or change Line p to make it?

[Barry]

Re: debug message in a template class

On Sep 30, 2:46 pm, thomas <FreshTho...@gm ail.comwrote:

template <class T>
class BufferQueue{
public:
          int BufferQueue<T>: :pushToQueue(T pkt, int timeout);
>
}
>
template<class T>
int BufferQueue<T>: :pushToQueue(T pkt, ACE_Time_Value *timeout){
          cout<<"in pushToQueue"<<e ndl;              --------Line p
          return 0;
>
}
>
Suppose I have two instances BufferQueue<A_a , BufferQueue<B_b ;
I want to know which instance I'm in by printing some debug messages
out in Line p
like
"in pushToQueue of A", etc.
>
How can I tell the compiler or change Line p to make it?

You can define a static memeber function like T::GetName() which
returns
the name of the class, so

cout << "in pushToQueue " << T::GetName() << endl;

Or you may have typeid(T).name( ) output as message.

[thomas]

Re: debug message in a template class

>
You can define a static memeber function like T::GetName() which
returns
the name of the class, so
>
cout << "in pushToQueue " << T::GetName() << endl;

How can you write the "GetName" method?

>
Or you may have typeid(T).name( ) output as message.- Hide quoted text -
>
- Show quoted text -

Yeah.. The typeid function should work. Thanks.

[James Kanze]

Re: debug message in a template class

On Sep 30, 11:18 am, thomas <FreshTho...@gm ail.comwrote:

[...]

Or you may have typeid(T).name( ) output as message.- Hide
quoted text -

Yeah.. The typeid function should work. Thanks.

It should, but whether it does or not is a quality of
implementation issue. As far as the standard is concerned, an
implementation which always returns "" is fully conforming. In
practice, most implementations (with the notable exception of
g++) do return something useful.

--
James Kanze (GABI Software) email:james.kan ze@gmail.com
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[Barry]

Re: debug message in a template class

On Sep 30, 5:18 pm, thomas <FreshTho...@gm ail.comwrote:

You can define a static memeber function like T::GetName() which
returns
the name of the class, so

>

cout << "in pushToQueue " << T::GetName() << endl;

>
How can you write the "GetName" method?
>

template <class T>
struct MyClass
{
void MyFunc() const
{
std::cout << T::GetName() << std::endl;
}
};

Here every instatiation of T is requred
to have a static function named "GetName";

struct T_type1
{
static char const* GetName() { return "T_type1"; }
};

int main()
{
MyClass<T_type1 c1;
c1.MyFunc();
}

>
>

Or you may have typeid(T).name( ) output as message.- Hide quoted text -

>

- Show quoted text -

>
Yeah.. The typeid function should work. Thanks.