Convert time to FILETIME

[nabil035]

hi,

wel I have these vars:

double day,month,year, hour,minute,sec ond,millisecond ;

I want to convert this data to a filetime structure, I don't want of course to convert them manually


please help

[arnaudk]

I think an int would be more appropriate... To copy those variables into a struct, you can use this syntax:
[code=cpp]
struct FileTime
{
int day;
int hour;
// etc
FileTime(const int& d, const int& h);
};

FileTime::FileT ime(const int& d, const int& h)
: day(d), hour(h)
{ }

int main()
{
int day = 1, hour = 23;
FileTime ft(day, hour);
cout << "The day is " << ft.day << endl;
}
[/code]

In C, structs can't have constructors. In that case you could define a function which takes your variables and a (pointer to a) struct, and sets the struct variables accordingly.

[nabil035]

Thx,

In fact, I don't want to define a new FileTime structure, I'd like to use the C predefined FILETIME structure.