Array of pointers

[Slain]

I am creating an array of char pointers.

char *str[2];
str[1]= "ma";

How ever the compiler gives me the following error. Any suggestions?

error: expected constructor, destructor, or type conversion before '='
token
error: expected `,' or `;' before '=' token

[pauldepstein@att.net]

Re: Array of pointers

On Mar 5, 10:34 am, Slain <Slai...@gmail. comwrote:

I am creating an array of char pointers.
>
char *str[2];
str[1]= "ma";
>
How ever the compiler gives me the following error.  Any suggestions?
>
error: expected constructor, destructor, or type conversion before '='
token
error: expected `,' or `;' before '=' token

I was mystified by this error too. So I tested it using Visual c++
and Windows XP with a std::cout statement std::cout<<str[1]; for
testing
I got the string ma as expected.

In other words, no this does not give any error on my machine. But
you've obviously posted a snippet rather than the full code because,
for example, there's no main. Could you please reproduce code in its
entirety which generates the error?

Paul Epstein

[Slain]

Re: Array of pointers

On Mar 4, 9:56 pm, pauldepst...@at t.net wrote:

On Mar 5, 10:34 am, Slain <Slai...@gmail. comwrote:
>

I am creating an array of char pointers.

>

char *str[2];
str[1]= "ma";

>

How ever the compiler gives me the following error. Any suggestions?

>

error: expected constructor, destructor, or type conversion before '='
token
error: expected `,' or `;' before '=' token

>
I was mystified by this error too. So I tested it using Visual c++
and Windows XP with a std::cout statement std::cout<<str[1]; for
testing
I got the string ma as expected.
>
In other words, no this does not give any error on my machine. But
you've obviously posted a snippet rather than the full code because,
for example, there's no main. Could you please reproduce code in its
entirety which generates the error?
>
Paul Epstein

I am declaring this as a global variable outside main. I use this
later in a function

int x= size/ strlen(str);
for (int ii=0;ii<x; ii++)
{
strcat(String1, str);
}

[Slain]

Re: Array of pointers

On Mar 4, 9:56 pm, pauldepst...@at t.net wrote:

On Mar 5, 10:34 am, Slain <Slai...@gmail. comwrote:
>

I am creating an array of char pointers.

>

char *str[2];
str[1]= "ma";

>

How ever the compiler gives me the following error. Any suggestions?

>

error: expected constructor, destructor, or type conversion before '='
token
error: expected `,' or `;' before '=' token

>
I was mystified by this error too. So I tested it using Visual c++
and Windows XP with a std::cout statement std::cout<<str[1]; for
testing
I got the string ma as expected.
>
In other words, no this does not give any error on my machine. But
you've obviously posted a snippet rather than the full code because,
for example, there's no main. Could you please reproduce code in its
entirety which generates the error?
>
Paul Epstein

I am declaring this as a global variable outside main. I use this
later in a function

int x= size/ strlen(str);
for (int ii=0;ii<x; ii++)
{
strcat(String1, str);
}

[Slain]

Re: Array of pointers

On Mar 4, 9:56 pm, pauldepst...@at t.net wrote:

On Mar 5, 10:34 am, Slain <Slai...@gmail. comwrote:
>

I am creating an array of char pointers.

>

char *str[2];
str[1]= "ma";

>

How ever the compiler gives me the following error. Any suggestions?

>

error: expected constructor, destructor, or type conversion before '='
token
error: expected `,' or `;' before '=' token

>
I was mystified by this error too. So I tested it using Visual c++
and Windows XP with a std::cout statement std::cout<<str[1]; for
testing
I got the string ma as expected.
>
In other words, no this does not give any error on my machine. But
you've obviously posted a snippet rather than the full code because,
for example, there's no main. Could you please reproduce code in its
entirety which generates the error?
>
Paul Epstein

I am declaring this as a global variable outside main. I use this
later in a function

int x= size/ strlen(str);
for (int ii=0;ii<x; ii++)
{
strcat(String1, str);
}

[pauldepstein@att.net]

Re: Array of pointers

On Mar 5, 11:02 am, Slain <Slai...@gmail. comwrote:

On Mar 4, 9:56 pm, pauldepst...@at t.net wrote:
>
>
>
>
>

On Mar 5, 10:34 am, Slain <Slai...@gmail. comwrote:

>

I am creating an array of char pointers.

>

char *str[2];
str[1]= "ma";

>

How ever the compiler gives me the following error.  Any suggestions?

>

error: expected constructor, destructor, or type conversion before '='
token
error: expected `,' or `;' before '=' token

>

I was mystified by this error too.  So I tested it using Visual c++
and Windows XP with a std::cout statement  std::cout<<str[1]; for
testing
I got the string ma as expected.

>

In other words, no this does not give any error on my machine.  But
you've obviously posted a snippet rather than the full code because,
for example, there's no main.  Could you please reproduce code in its
entirety which generates the error?

>

Paul Epstein

>
I am declaring this as a global variable outside main. I use this
later in a function
>
int x= size/  strlen(str);
        for (int ii=0;ii<x; ii++)
        {
                 strcat(String1, str);
        }- Hide quoted text -
>
- Show quoted text -

strlen(str) doesn't make sense to me. strlen means stringlength but
str is not a string as you've defined it. I have no idea what you
mean by strlen(str);

Paul Epstein

[Slain]

Re: Array of pointers

On Mar 4, 10:31 pm, pauldepst...@at t.net wrote:

On Mar 5, 11:02 am, Slain <Slai...@gmail. comwrote:
>
>
>

On Mar 4, 9:56 pm, pauldepst...@at t.net wrote:

>

On Mar 5, 10:34 am, Slain <Slai...@gmail. comwrote:

>

I am creating an array of char pointers.

>

char *str[2];
str[1]= "ma";

>

How ever the compiler gives me the following error. Any suggestions?

>

error: expected constructor, destructor, or type conversion before '='
token
error: expected `,' or `;' before '=' token

>

I was mystified by this error too. So I tested it using Visual c++
and Windows XP with a std::cout statement std::cout<<str[1]; for
testing
I got the string ma as expected.

>

In other words, no this does not give any error on my machine. But
you've obviously posted a snippet rather than the full code because,
for example, there's no main. Could you please reproduce code in its
entirety which generates the error?

>

Paul Epstein

>

I am declaring this as a global variable outside main. I use this
later in a function

>

int x= size/ strlen(str);
for (int ii=0;ii<x; ii++)
{
strcat(String1, str);
}- Hide quoted text -

>

- Show quoted text -

>
strlen(str) doesn't make sense to me. strlen means stringlength but
str is not a string as you've defined it. I have no idea what you
mean by strlen(str);
>
Paul Epstein

Yes!!! That part of the code was before I tried to make str an array
if pointers. When I used the strlen I just used the str as a char
pointer.

Thanks
manny

[Ian Collins]

Re: Array of pointers

Slain wrote:

>
Yes!!! That part of the code was before I tried to make str an array
if pointers. When I used the strlen I just used the str as a char
pointer.
>

Is there a good reason why you can't use std::string?


--
Ian Collins.

[pauldepstein@att.net]

Re: Array of pointers

On Mar 5, 11:34 am, Slain <Slai...@gmail. comwrote:

On Mar 4, 10:31 pm, pauldepst...@at t.net wrote:
>
>
>
>
>

On Mar 5, 11:02 am, Slain <Slai...@gmail. comwrote:

>

On Mar 4, 9:56 pm, pauldepst...@at t.net wrote:

>

On Mar 5, 10:34 am, Slain <Slai...@gmail. comwrote:

>

I am creating an array of char pointers.

>

char *str[2];
str[1]= "ma";

>

How ever the compiler gives me the following error.  Any suggestions?

>

error: expected constructor, destructor, or type conversion before'='
token
error: expected `,' or `;' before '=' token

>

I was mystified by this error too.  So I tested it using Visual c++
and Windows XP with a std::cout statement  std::cout<<str[1]; for
testing
I got the string ma as expected.

>

In other words, no this does not give any error on my machine.  But
you've obviously posted a snippet rather than the full code because,
for example, there's no main.  Could you please reproduce code in its
entirety which generates the error?

>

Paul Epstein

>

I am declaring this as a global variable outside main. I use this
later in a function

>

int x= size/  strlen(str);
        for (int ii=0;ii<x; ii++)
        {
                 strcat(String1, str);
        }- Hide quoted text -

>

- Show quoted text -

>

strlen(str)  doesn't make sense to me.  strlen means stringlength but
str is not a string as you've defined it.  I have no idea what you
mean by strlen(str);

>

Paul Epstein

>
Yes!!! That part of the code was before I tried to make str an array
if pointers. When I used the strlen I just used the str as a char
pointer.
>
Thanks
manny- Hide quoted text -
>
- Show quoted text -

I don't understand why you say "Yes!!!" What question are you
answering "Yes!!!" to? It seems that "Yes!!!" should be replaced by
"Sorry for the confusion I caused."


Paul Epstein

[faizulhaquezeya@gmail.com]

Re: Array of pointers

On Mar 5, 7:34 am, Slain <Slai...@gmail. comwrote:

I am creating an array of char pointers.
>
char *str[2];
str[1]= "ma";
>
How ever the compiler gives me the following error.  Any suggestions?
>
error: expected constructor, destructor, or type conversion before '='
token
error: expected `,' or `;' before '=' token

you are not allocating memory for that.
faiz ul haque zeya
Transys

[pelio]

Re: Array of pointers

Slain dixit:

On Mar 4, 9:56 pm, pauldepst...@at t.net wrote:

>On Mar 5, 10:34 am, Slain <Slai...@gmail. comwrote:
>>

>>I am creating an array of char pointers.
>>char *str[2];
>>str[1]= "ma";
>>How ever the compiler gives me the following error. Any suggestions?
>>error: expected constructor, destructor, or type conversion before '='
>>token
>>error: expected `,' or `;' before '=' token

>I was mystified by this error too. So I tested it using Visual c++
>and Windows XP with a std::cout statement std::cout<<str[1]; for
>testing
>I got the string ma as expected.
>>
>In other words, no this does not give any error on my machine. But
>you've obviously posted a snippet rather than the full code because,
>for example, there's no main. Could you please reproduce code in its
>entirety which generates the error?
>>
>Paul Epstein

>
I am declaring this as a global variable outside main. I use this
later in a function

If your code is like that:

char *str[2]; // line 1
str[1] = "ma"; // line 2

// ...

int main()
{
}

be aware that line 2 is illegal.

>
int x= size/ strlen(str);
for (int ii=0;ii<x; ii++)
{
strcat(String1, str);
}
>